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Phantasy [73]
3 years ago
6

Which figure shows the correct dimensions of a 1/3 scale drawing of the given figure

Mathematics
1 answer:
Romashka [77]3 years ago
8 0

Answer:

Ok I cannot see the figure but let me explain to you how to do this. If you see the and know the measurements, just divide all the measurements by 3 and draw the figure again. If I have a rectangle with side lengths 12 and 9, and I want to draw a 1/3 scale drawing, I would divide 12/3 = 4 and 9/3 = 3. So your new side-lengths are 4 and 3. I hoped this helped a little!!

Step-by-step explanation:

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Determine if the sequence below is arithmetic or geometric and determine the
Sonbull [250]

Answer: Arithmetic and 3

Step-by-step explanation:

12 - 9 = 3 9 - 6 = 3 The common difference is equal and is three and so it is an arithmetic sequence

12/9 = 4/3 9/6 = 3/2 The ratio is not equal so this is not a geometric sequence

4 0
2 years ago
True or false? f (x) = 2 · (1/5)^x represents an exponential function growth.
nekit [7.7K]

Hi there!

\large\boxed{\text{False.}}

f(x) = 2(1/5)ˣ

Recall the form of an exponential function:

f(x) = a(b)ˣ where:

a = initial value

b = rate of decay/growth

If b > 1, the function is undergoing exponential growth. If b < 1, then the function is undergoing exponential decay.

1/5 < 1, so the function is undergoing exponential decay, not growth.

7 0
3 years ago
Find the missing factor BBB that makes the equality true.
loris [4]

Answer:21y^4= B*7y^3

B=(21y^4)/(7y^3)

B=3y

i think this is correct

4 0
3 years ago
The candy store is having a 30% off sale. Emma is going to buy $12.50 worth of candy. How much will she pay after the discount?
Fantom [35]
$16.25. You do 30% of $12.50 and then add it on
4 0
3 years ago
Read 2 more answers
What is the sum of the first 30 terms of this arithmetic sequence? 6,13,20,27,34
Galina-37 [17]

Answer:

3135

Step-by-step explanation:

Givens

a1 = 6

Use t4 - t3 to get d

t4 = 27

t3 = 20

Step One

Find a1 and d

a1 = 6

d = t4 - t3

d = 27 - 20

d = 7

Step Two

Find the 30th Term

tn= a1 + (n -1 )*d

t30 = 6 + (30 - 1) * 7

t30 = 6 + 29*7

t30 = 6 + 203

t30 = 209

Step Three

Find the sum using Sum = (a + t30)*n/2

n = 30              given

a1 = 6               given  

t30 = 209         calculated from step 2

Sum = (a1 + t30)*n/2        Substitute

Sum = (6+ 209)*30/2       Combine like terms and divide by 2

sum = 215 * 15                  Multiply

Sum = 3135                      Answer

4 0
3 years ago
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