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Dennis_Churaev [7]
3 years ago
6

Graph each system and determine the number of solutions it has. If it has one solution, name it.

Mathematics
1 answer:
Naya [18.7K]3 years ago
5 0

I have the picture here:

  1. One Solution (-1,-2)
  2. One Solution (2,-3)
  3. One Solution (1/2,2)
  4. One Solution (1,4)
  5. No Solution
  6. Infinite Solutions

Hope this helps!

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Kaylee made a scale drawing of a house and its lot. The scale of the drawing was 1 inch : 5 feet. If the backyard deck is 7 inch
Luden [163]

Answer:

35 feet

Step-by-step explanation:

if 1 inch = 5 feet

if the scale drawing is 7 inches, the width of the deck = 7 x 5 = 35 feet

8 0
3 years ago
Which equation represents a graph with a vertex at (1,-6)?
aivan3 [116]

Answer:

B.y = 3x2 - 6x - 3 is the second option of the options provided as the solution.

Write y+6=3(x2-1)2=> y+6=3x2-6x+3=> y=3x2-6x-3 as the justification.

3 0
1 year ago
Help me with this exercise !!! If the answer is correct i will give to you a Brainlist
IceJOKER [234]
The answer is B) (6,-8.75).
3 0
3 years ago
Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin
ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let \mu = <em><u>mean duration of 15-sided union rugby games after the meeting.</u></em>

So, Null Hypothesis, H_0 : \mu \geq 185 minutes      {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, H_A : \mu < 185 minutes     {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean duration of 15-sided union rugby games = 179 min

            s = sample standard deviation = 12 minutes

            n = sample of 15-sided rugby games = 36

So, <u><em>the test statistics</em></u>  =  \frac{179-185}{\frac{12}{\sqrt{36} } }  ~ t_3_5

                                       =  -3

The value of t test statistics is -3.

<u>Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

6 0
3 years ago
If SV⊥RT, m∠RSU = (17x – 3)°, and m∠UST = (6x – 1)°, find TSV
goblinko [34]

Applying the linear pair theorem, the measure of angle TSV in the image given is: 86°.

<h3>How to Apply the Linear Pair Theorem?</h3>

Given the following angles in the image above:

Measure angle RSU = (17x - 3)°,

Measure angle UST = (6x – 1)°

To find the measure of angle TSV, we need to find the value of x in the given expressions as shown below:

m∠RSU + m∠UST = 180 degrees (linear pair]

Substitute the values

17x - 3 + 6x - 1 = 180

Solve for x

23x - 4 = 180

23x = 180 + 4

23x = 184

x = 8

m∠TSV = 180 - 2(m∠UST) [Linear Pair Theorem]

m∠TSV = 180 - 2(6x - 1)

Plug in the value of x

m∠TSV = 180 - 2(6(8) - 1)

m∠TSV = 86°

Therefore, applying the linear pair theorem, the measure of angle TSV in the image given is: 86°.

Learn more about the linear pair theorem on:

brainly.com/question/5598970

#SPJ1

6 0
1 year ago
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