Answer:
I would say use photomath if you cant find your answer.
Step-by-step explanation:
The surface area of the right triangular prism is 270 sq ft
<h3>Total surface ara of the prism</h3>
The total surface area of the prism is the sum of all the area of its faces
For the two triangles
A = 2(0.5bh)
A = bh
A = 7 * 12 = 84 sq.ft
For the two rectangles
A = 2lw
A = 2(6*12)
A = 2 * 72 = 144 sq.ft
For the third triangle;
Area 6ft * 7ft
Area = 42 sq.feet
Taking the sum of the areas
TSA = 84 + 144 + 42
TSA = 270 sq ft
Hence the surface area of the right triangular prism is 270 sq ft
Learn more on surface area of prism here; brainly.com/question/1297098
Answer:
m∠CFD is 70°
Step-by-step explanation:
In the rhombus
- Diagonals bisect the vertex angles
- Every two adjacent angles are supplementary (their sum 180°)
Let us solve the question
∵ CDEF is a rhombus
∵ ∠E and ∠F are adjacent angles
→ By using the second property above
∴ ∠E and ∠F are supplementary
∵ The sum of the measures of the supplementary angles is 180°
∴ m∠E + m∠F = 180°
∵ m∠E = 40°
∴ 40° + m∠F = 180°
→ Subtract 40 from both sides
∵ 40 - 40 + m∠F = 180 - 40
∴ m∠F = 140°
∵ FD is a diagonal of the rhombus
→ By using the first property above
∴ FD bisects ∠F
→ That means FD divides ∠F into 2 equal angles
∴ m∠CFD = m∠EFD = 
m∠F
∴ m∠CFD = (140°)
∴ m∠CFD = 70°
Answer:
y^2 - 5y - 4
Step-by-step explanation:
So you want f(y) such that
(y^2-5y+1) - f(y) = 5
Subtract both sides by (y^2-5y+1):
-f(y) = 5 - (y^2-5y+1)
-f(y) = -y^2 + 5y + 4
f(y) = y^2 - 5y - 4
So the polynomial you are looking for is y^2 - 5y - 4
Answer:0.36
or 36
Step-by-step explan: used calculator
