Answer:
The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs is the answer.
Step-by-step explanation:
given that Ty and Gajge are football players.
Carries is 15 for both and average is the same 4 for both.
But on scrutiny we find that maximum and minimum and 6 and 2 for Ty.
Hence range for Ty = 6-2 =4 (2 runs on eithre side of mean)
But for Gajge, highest is 19 and lowest is 2.
i.e. range = 19-2 =17 very much higher than that of Ty
The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs.
Answer:
4.5 x 2
Step-by-step explanation:
4.5 x 2 = 9
Hope it helps
20/21 is the answer to your problem.
Answer:
12a^2 - 9a + 5
Step-by-step explanation:
(5a^2 - 6a - 4) - (-7a^2 + 3a - 9)
5a^2 + 7a^2 = 12a^2
-6a - 3a = -9a
-4 + 9 = 5
12a^2 - 9a + 5
Take the common denominator and divide by 3 then youll get 58
