Percy works two part-time jobs to help pay for college classes. On Monday, he works 3 hours at the library and 2 hours at the co
ffee cart and earns $36.50. On Tuesday, he works 2 hours at the library and 5 hours at the coffee cart and earns $50. His hourly wage at the library, x, and hourly wage at the coffee cart, y, can be determined using the system of equations below3x + 2y = 36.50 2x + 5y = 50.00
At which job does Percy earn the greater hourly wage? How much does Percy earn each hour at this job?
For the answer to the two questions above, 3x + 2y = 36.50 (I) 2x + 5y = 50 (II) Eliminating x from the two equations by subtraction: first we multiply equation I by 2 and equation II by 3 6x + 4y = 73 6x + 15y = 150 Subtracting the two, -11y = -77 y = 7 He earns $7 at the coffee cart Substituting y into equation I, 3x + 14 = 36.5 x = $7.50
So we can conclude that, he earns a greater wage of $7.50 at the library,
Hello there. <span> Percy works two part-time jobs to help pay for college classes. On Monday, he works 3 hours at the library and 2 hours at the coffee cart and earns $36.50. On Tuesday, he works 2 hours at the library and 5 hours at the coffee cart and earns $50. His hourly wage at the library, x, and hourly wage at the coffee cart, y, can be determined using the system of equations below3x + 2y = 36.50 2x + 5y = 50.00 At which job does Percy earn the greater hourly wage? How much does Percy earn each hour at this job? </span> x = $7.50
We know that A relationship between two variables, x, and y,<span> is proportional if it can be expressed in the form y/x=k or y=kx</span> in this problem k=2 then y=2x