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3 years ago

The number can be divided by the least common multiple of 3 and 5

Mathematics

1 answer:

kondaur [170]3 years ago

3 0

9514 1404 393

Answer:

255

Step-by-step explanation:

If the sum of digits is 12, the number is divisible by 3. If the number ends in 0 or 5, it is divisible by 5. So, we're looking for ...

2x0 . . . where x is a digit and 2+x+0 = 12 . . . . . . not possible

2x5 . . . where x is a digit and 2+x+5 = 12 . . . . true for x=5

The number is 255.

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400 meters to 350 meters

OleMash [197]

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8 0

3 years ago

For the real-valued functions f(x)=2x+3 and g(x)=√x-5, find the composition fog and specify its domain using interval notation.

Burka [1]

Find fog

fog(x)
f(g(x))
f(√x-5)
2√(x-5)+3

For real range the domain

x-5≥0
x≥5

Domain is [5,oo)

7 0

2 years ago

Write the standard form of the equation of the circle with the given characteristics. Center: (3, 5); Solution point: (−2, 17)

Angelina_Jolie [31]

$\text{we know that the general equation of the circle is }\\
\\
(x-h)^2+(y-k)^2=r^2\\
\\
\text{where, (h,k) is the center of the circle and r is the radius.}\\
\\
\text{Given that the centered of the circle is at }(h,k)=(3,5)\\
\text{and a solution point on circle is (-2,17).}\\
\\
\text{so the radius of the circle will be the distance between center and the }$

$\text{solution point. so using the distance formula, we have}\\
\\
\text{Radius, }r=\sqrt{(-2-3)^2+(17-5)^2}\\
\\
\Rightarrow r=\sqrt{25+144}\\
\\
\Rightarrow r=\sqrt{169}\\
\\
\Rightarrow r=13\\
\\
\text{Hence using the standard for of circle, equation of circle with center}\\
(h,k)=(3,5) \text{ and radius r=13 is}\\
\\
(x-3)^2+(y-5)^2=(13)^2\\
\\
\Rightarrow (x-3)^2+(y-5)^2=169$

3 0

3 years ago

I need help please.

Ivan

1. It is given that f(x) is 16 times the square root of x.

Putting that in mathematical terms we have,

f(x) = 16 * $\sqrt{x}$

also, y = f(x)

So, we have the function

y= 16 $\sqrt{x}$

4. We need to solve the inequality equation : 4x + 2y ≤ 6

Let us take the equation,

4x+2y ≤ 6

2y ≤ 6-4x

y ≤ $\frac{6-4x}{2}$

y ≤ 3-2x

So, any point (x,y) lies on the given inequality region, where y≤ 3-2x

5. Solving system of equations using addition method

Given:

-5x-y =38 ------> a

-6x-3y =60 -------> b

Divide the equation b by no. 3

(-6x-3y)/3 = 60/3

-2x-y = 20 -------> c

Subtracting equation c from a we have,

-5x-y - (-2x-y) = 38 - 20

-5x-y+2x+y = 18

-3x = 18

x = -6

Now, substituting the value of x in equation a, we get

-5(-6) - y =38

30-y =38

y= 30-38 = -8

y=-8

∴ x = -6 and y = -8

6. Finding composition of functions

Given : f(x) =15x + 7 ; g(x) = x² - 5x

To find : (f+g)(x)

(f+g) (x) = f(g(x))

So, replace the value of x in f(x) by g(x), where g(x)= x² - 5x

(f+g)(x) = 15(x²-5x) +7 =15x²-75x+7

∴ (f + g)(x) = 15x²-75x+7

7. System of 3 equations must be solved to find the solution

-8x-8y-5z=-6

7x-8y-9z =17

9x+2y+6z =-1

Solving by substitution method.

Isolate x from first equation :

x= (-6+8y+5z)/(-8)

Substitute this value of x in 2nd and 3rd equations.

$7 (- \frac{-6+8y+5z}{8})-8y -9z = 17$

$9(- \frac{-6+8y+5z}{8}) + 2y + 6z = -1$

Now, isolating y from the 2nd equation rewritten above, we have

y= - $\frac{107 z + 94}{120}$

Now substituting this value of y in the 3rd equation rewritten above, we have

$9(- \frac{-6+8(-\frac{107 z + 94}{120})+5z}{8}) + 2(-\frac{107 z + 94}{120}) + 6z = -1$

Isolating z from above equation, we have

z = -2

Substitute z= -2 in the equation of y, we have

y= - $\frac{107 (-2) + 94}{120}$ = 1

y = 1

Substituting the value of y and z, in the equation of x, we have

x= (-6+8(1)+5(-2))/(-8) = 1

x = 1

∴ x=1 ; y = 1 ; z = -2

8. 5x ≤ 7

Solving the above equation, we have

x ≤ 7/5

Please see attachment for the graph.

9. The given function is : g(y) = $\sqrt{y}$ -6

The domain is the set of values of y for which there can be a value of g(y).

Here g(y) can be real only if y is greater than or equal to 0.

∴ The domain of the given function is [0,∞) .

10. Given : y is a function of x.

Definition of function : A function is a relation that associates each element in the domain to one element of another set, the co-domain of the function.

∴ For each element x, in the domain, there is only one value of y in the range.

4 0

3 years ago

Please help me here

Natasha2012 [34]

Answer:

Step-by-step explanation:

C because you multiply the nimbers and then divid.

3 0

3 years ago