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Aleksandr-060686 [28]
3 years ago
6

Can someone help me turn these two word problems into algebraic expressions?

Mathematics
1 answer:
Dima020 [189]3 years ago
5 0
1. N=x+3
    S=2(x+3), or Sam=2x+6
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Ax+by=c<br> с.<br> a<br> What is the value of x?
Sergeeva-Olga [200]

Answer:

ax + by = c \\ ax = c - by \\ { \boxed{ \boxed{x =  \frac{c - by}{a} }}}

3 0
2 years ago
Need help with my problem of the day it’s confusing I’m not good at math :| HELP
alex41 [277]

Answer:

7:36

Step-by-step explanation:


4 0
3 years ago
Help please ASAP thank you
jonny [76]

<u>Question 1</u>

If we let FE=x, then DE=x-5.

Also, as \overline{DF} bisects \overline{BC}, this means BE=EC=6.

Thus, by the intersecting chords theorem,

6(6)=x(x-5)\\\\36=x^2 - 5x\\\\x^2 - 5x-36=0\\\\(x-9)(x+4)=0\\\\x=-4, 9

However, as distance must be positive, we only consider the positive case, meaning FE=9

<u>Question 2</u>

If we let CE=x, then because AB bisects CD, CE=ED=x.

We also know that since FB=17, the radius of the circle is 17. So, this means that the diameter is 34, and as AE=2, thus means EB=32.

By the intersecting chords theorem,

2(32)=x^2\\\\64=x^2\\\\x=-8, 8

However, as distance must be positive, we only consider the positive case, meaning CE=8

4 0
2 years ago
Abby used the quadratic formula to find the zeros of the
MArishka [77]

Step 2: She did not simplify under the square root correctly

under the square root:

(-6)^2 =36

and -4(5)(-8) =160

therefore under the square root it needs to be square root of 36+160 which is square root of 196.

That answer is 14 when square rooted

5 0
2 years ago
Read 2 more answers
Write in standard form:<br> 4 (2a) + 7 (-4b) + (3.c - 5)<br><br> * The . is a multiplication sign.
alisha [4.7K]
Refer to cy math.com  they have the answer 
3 0
3 years ago
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