Answer:
Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for the remaining variables.
X = 1
Y = 2
Hello,
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Answer B
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2x²+28x-5=2(x²+2*7x+49)-5-2*49=2(x+7)²-103
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Answer:
B and D
Step-by-step explanation:
B:
Anything to a negative power means that it is 1/that to the positive power.
E.g. x^-1 = 1/x^1
In other words, anything to the power of a negative switches sides of a fraction (i.e. if in numerator moves to denominator and vice versa.)
1/x^-1 = 1/1/x^1 which is just equal to x, because there are x number of 1/xs in one (1/x * x =1) Therefore Option B is equal to just x.
D: (assuming the first given term is x^1/3 and not X1/3 (?) Correct me if I'm wrong).
x^1/3 * x^1/3 * x^1/3 is also equal to just x.
This is because when multiplying together terms with the same base (x in this case) the exponents just add together, so:
x^1/3 * x^1/3 * x^1/3 = x^(1/3 +1/3 +1/3) = x^1 = x.
Therefore B and D are equivalent because they both equal x.
Hope this helped!
P3(4) = p12 them p12 * p8 = P160 (false)
