All categories

3 years ago

Which answers describe the shape below? Check all that apply.

Mathematics

1 answer:

My name is Ann [436]3 years ago

8 0

Answer:

E and C

Step-by-step explanation:

You might be interested in

Write the standard form of the line with the given information. Include your work in your final answer. Type your answer in the

AURORKA [14]

Answer:

The standard form of line is

$-3x+y=-2$

Step-by-step explanation:

we are given a line

slope=3

so,

$m=3$

y-intercept of -2

so,

$b=-2$

now, we can use slope-intercept form of line

$y=mx+b$

now, we can plug values

$y=3x-2$

we can write it in standard form of line

$ax+by=c$

$y=3x-2$

we can subtract both sides by 3x

$y-3x=3x-2-3x$

$y-3x=-2$

$-3x+y=-2$

So, the standard form of line is

$-3x+y=-2$

3 0

3 years ago

Read 2 more answers

Devon made a box with length x+1, width x+3, and height x-3. What is the volume of Devon's box as a function of x?

erica [24]

Answer:

(a)

$V=x^3+x^2-9x-9$

(b)

$x=10$

(c)

$x=\frac{7}{2}$

Step-by-step explanation:

we are given

length is x+1

$L=x+1$

width is x+3

$W=x+3$

height is x-3

$H=x-3$

(a)

we can use volume formula

$V=L\times W\times H$

now, we can plug it

$V=(x+1)\times (x+3)\times (x-3)$

now, we can simplify it

$V=x^3+x^2-9x-9$

(b)

we are given volume =1001

so, we can set V=1001

and then we can solve for x

$V=x^3+x^2-9x-9=1001$

now, we can factor it

$\left(x-10\right)\left(x^2+11x+101\right)=0$

$x-10=0$

$x=10$

(b)

we are given volume

so, we can set

$V=14\frac{5}{8}=\frac{14\times 8+5}{8}$

$V=\frac{117}{8}$

and then we can solve for x

$V=x^3+x^2-9x-9=\frac{117}{8}$

now, we can factor it

$8x^3+8x^2-72x-189=0$

$\left(2x-7\right)\left(4x^2+18x+27\right)=0$

$2x-7=0$

$x=\frac{7}{2}$

8 0

3 years ago

Write an equation of a like that passes through the points (9,5) and (6,7)

hodyreva [135]

Answer:

y=-2/3x+11

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(7-5)/(6-9)

m=2/-3

m=-2/3

y-y1=m(x-x1)

y-5=-2/3(x-9)

y=-2/3x+18/3+5

y=-2/3x+6+5

y=-2/3x+11

5 0

3 years ago

A sandbox has an area of 10 2/3 square feet, and the length is 1/4 feet. What is the width of the sandbox?

AlekseyPX

Answer:

The width of the sandbox is $42\frac{2}{3} \ ft$ .

Step-by-step explanation:

Given,

Area of the sandbox = $10\frac{2}{3}=\frac{32}{3}\ ft^2$

Length = $\frac{1}{4}\ ft$

Solution,

Let the width of the sandbox be 'w'.

Since the sandbox is in shape of rectangle.

So we use the formula of area of rectangle.

$Area = Length\times Width$

On substituting the given values, we get;

$\frac{1}{4}\times w=\frac{32}{3}\\$

By cross multiplication method, we get;

$w=\frac{32\times4}{3\times 1} =\frac{128}{3} =42\frac{2}{3} \ ft$

Hence The width of the sandbox is $42\frac{2}{3} \ ft$ .

5 0

3 years ago

Katya measured the growth of a plant seedling. The seedling grew 1/3 inch by the end of the first week and another 5 / 6 inch by

cupoosta [38]

The seedling grew 1 1/6 inches or approximately 1.16 inches. 1/3 is equal to 2/6, 2/6 + 5/6 = 7/6
7/6 = 1 1/6

4 0

3 years ago

Read 2 more answers