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Kipish [7]
3 years ago
5

The triangles shown are congruent by the SSS congruence theorem.

Mathematics
2 answers:
Keith_Richards [23]3 years ago
6 0

Answer:

B. Rotation, then Translation, then Reflection

Step-by-step explanation:

I got the answer right on Ingenuity.

The site doesn't let me put Ingenuity with an E instead of an I at the front.

denis23 [38]3 years ago
3 0
1. Let's check the problem backwards. So let's map A"B"C" to ABC

2. We first need to reflect  A"B"C" to A"B"C' with A"B"" as the axis of rotation.

3. Then we shift a few units up (translation) A"B"C' to A'B'C

4. Finally we rotate A'B'C around C to map the triangle onto ABC

going backwards we get the answer: b

<span>b.rotation, then translation, then reflection</span>

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8 0
3 years ago
How do i find LM? On number 2 .
Masja [62]
Given: KL is a tangent to the circle.
LM is another tangent to the circle.

We can use the tangent meeting at an external point theorem.
<em>Theorem</em>: <em>The tangent segments to a circle from an external point are equal.
</em>
Thus, we can say KL = LM, as they lie on a common circle, and are tangents to such circle.

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