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Grace [21]
2 years ago
13

Solve for x to the nearest tenth

Mathematics
2 answers:
Bess [88]2 years ago
8 0
Equal 5 square foot
Lady_Fox [76]2 years ago
6 0
3^2+4^2=
9+16=25
Square root of 25= 5

Answer: 5
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2 years ago
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ON TIMER!!!
Anton [14]

Answer:

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8 0
2 years ago
ABCD Is a rectangle that represents a park.
Andru [333]

Answer:

Shortest distance from A to C = 102.9005 m.

Step-by-step explanation:

It is given that, ABCD is a rectangular park.

The length of the park is 80 m.

The breadth of the park is 50 m.

The diameter of the circle = 15 m.

We have to calculate the shortest distance from A to C across the park.

The distance AC = \sqrt{50^{2}+80^{2} } = 94.339 m.

As one has to pass only through the lines shown, he cannot pass through the circle.

So, we have to subtract the diameter of 15 m from AC

=> 94.339 m - 15 m = 79.339 m.

One must pass through either half of the circumference of the circle.

Since, diameter of circle = 15 m, its radius(r) = \frac{15}{2} = 7.5 m.

The circumference of the circle = 2×π×r = 47.123 m.

Half of the circumference = \frac{47.123}{2} = 23.5615 m.

Distance from A to C passing through circumference = 79.339 m + 23.5615 m = 102.9005 m.

As we have to calculate the shortest distance from A to C, one cannot pass  from A to C either through B or D,

since the distance ABC or ADC = 50+80 = 130 m.

Therefore, shortest distance from A to C = 102.9005 m.

3 0
3 years ago
Read 2 more answers
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