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3 years ago

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A person 5.4 feet tall stands in line of a shadow cast from the top of the house. The shadow hits the top of the person's head,

and continues until the shadow ends on the ground 2.4 feet from the person's shoes. The distance along the ground from the tip of the shadow to the house is 14.6 feet. Find the height of the house. Do not round your

1 answer:

Sveta_85 [38]3 years ago

8 0

Check the picture below.

solve for "y".

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Describe the transformations needed to translate the graph y=1/x to the graph of y=1/x+3 -4

S_A_V [24]

i cant describe but i put y=1/x+3 -4 on the graph hope this helps

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2 years ago

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Question 2 of 25

tekilochka [14]

Answer: The Answer is C 2.29

Step-by-step explanation: I just got it right on the test

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2 years ago

33 1/3% of 360 please help I don’t understand

Mars2501 [29]

Answer:

33 1/3% of 360 is 120

Step-by-step explanation:

33 1/3 can be converted to 33.333% or simply just 1/3, divide 360 by 3 to get your answer which is 120.

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2 years ago

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The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2). On a coordinate plane, line A B has points (4, 1) and (n

GarryVolchara [31]

Answer:

$(-1,1),(4,-2)$

Step-by-step explanation:

Given: The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).

To find: coordinates of vertex of the right angle

Solution:

Let C be point $(x,y)$

Distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$AC=\sqrt{(x-4)^2+(y-1)^2}\\BC=\sqrt{(x+1)^2+(y+2)^2}\\AB=\sqrt{(4+1)^2+(1+2)^2}=\sqrt{25+9}=\sqrt{34}$

ΔABC is a right angled triangle, suing Pythagoras theorem (square of hypotenuse is equal to sum of squares of base and perpendicular)

$34=\left [ (x-4)^2+(y-1)^2 \right ]+\left [ (x+1)^2+(y+2)^2 \right ]$

Put $(x,y)=(-1,1)$

$34=\left [ (-1-4)^2+(1-1)^2 \right ]+\left [ (-1+1)^2+(1+2)^2 \right ]\\34=25+9\\34=34$

which is true. So, $(-1,1)$ can be a vertex

Put $(x,y)=(4,-2)$

$34=\left [ (4-4)^2+(-2-1)^2 \right ]+\left [ (4+1)^2+(-2+2)^2 \right ]\\34=9+25\\34=34$

which is true. So, $(4,-2)$ can be a vertex

Put $(x,y)=(1,1)$

$34=\left [ (1-4)^2+(1-1)^2 \right ]+\left [ (1+1)^2+(1+2)^2 \right ]\\34=9+4+9\\34=22$

which is not true. So, $(1,1)$ cannot be a vertex

Put $(x,y)=(2,-2)$

$34=\left [ (2-4)^2+(-2-1)^2 \right ]+\left [ (2+1)^2+(-2+2)^2 \right ]\\34=4+9+9\\34=22$

which is not true. So, $(2,-2)$ cannot be a vertex

Put $(x,y)=(4,-1)$

$34=\left [ (4-4)^2+(-1-1)^2 \right ]+\left [ (4+1)^2+(-1+2)^2 \right ]\\34=4+25+1\\34=30$

which is not true. So, $(4,-1)$ cannot be a vertex

Put $(x,y)=(-1,4)$

$34=\left [ (-1-4)^2+(4-1)^2 \right ]+\left [ (-1+1)^2+(4+2)^2 \right ]\\34=25+9+36\\34=70$

which is not true. So, $(-1,4)$ cannot be a vertex

So, possible points for the vertex are $(-1,1),(4,-2)$

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3 years ago

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masha68 [24]

Answer:

y = 0.64w + 12.60

Step-by-step explanation:

<u>This is a linear relationship y= mx + b and:</u>

The y-intercept is b = 12.60
The slope is m = 0.64

<u>The monthly total is:</u>

y = 0.64w + 12.60

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2 years ago