The formula for the quadratic formula is x (c in this case) = (-b(+/-)√(b²-4ac))/2a
This is used for an equation in standard quadratic form: ax² + bx + c = 0
1.) Put it in the correct form, if not already in it.
Ex. c² + 6c + 8 = 0
2.) Identify each part of the equation:
a = 1 (the leading coefficient), b = 6 (the coefficient in front of the second variable), c = 8
3.) Plug in each variable answer
c = (-6(+/-)√(6²-4(1)(8))/2(1)
4.) Simplify
c = (-6(+/-)√(36-(4*8))/2
c = (-6(+/-)√(36-32))/2
c = (-6(+/-)√(4))/2
c = (-6(+/-)2)/2
*Here, the equation splits in two. It becomes:
c = (-6+2)/2 AND c = (-6-2)/2
*Simplify again:
c = -4/2 AND c = -8/2
c = -2 AND c = -4
The answers c = -2 and c = -4 would solve the given equation.
Hope this helps! :)
The answer should be n=-8
Answer: the population after 5 years is 10814
Step-by-step explanation:
The population growth of the deer is exponential. We would apply the formula for determining exponential growth which is expressed as
A = P(1 + r)^t
Where
A represents the population after t years.
n represents the period of growth
t represents the number of years.
P represents the initial population.
r represents rate of growth.
From the information given,
P = 10289
r = 1% = 1/100 = 0.01,
t = 5 years
Therefore,
A = 10289(1 + 0.01)^5
A = 10289(1.01)^5
A = 10814
Parallel lines have the same slope.
So I plug in the -5 and -4
-4 = 1/2(-5) + b
-4 = -2.5 + b
b = -1.5
So I get y = 1/2x - 3/2
