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LenKa [72]
3 years ago
15

In how many ways can you arrange 3 out of 5 books (a, b, c, d, and

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
3 0
Yes bro...
the easiest way is to use 5C3
= 5! /(5-3)!3!
= 5(5-1)(5-2)(5-3)!/ (5-3)!3!
= 5×4×3×2/3×2
= 5×4 = 20ways
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\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
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\\ \quad \\
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\\ \quad \\
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\bf \begin{array}{llll}
% right side info
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\\\\

\end{array}\\

\bf \begin{array}{llll}
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
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now, notice the template above... now let's see your function \bf y=x^2+4\implies 
\begin{array}{llllll}
y=&1(&1x&+&0)^2+&4\\
&A&B&&C&D
\end{array}

so.. what do you think was the shift then?
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