Answer:
Midpoint of side EF would be (-.5,4.5)
Step-by-step explanation:
We know that the coordinates of a mid-point C(e,f) of a line segment AB with vertices A(a,b) and B(c,d) is given by:
e=a+c/2,f=b+d/2
Here we have to find the mid-point of side EF.
E(-2,3) i.e. (a,b)=(2,3)
and F(1,6) i.e. (c,d)=(1,6)
Hence, the coordinate of midpoint of EF is:
e=-2+1/2, f=3+6/2
e=-1/2, f=9/2
e=.5, f=4.5
SO, the mid-point would be (-0.5,4.5)
Your answer can be anything in the form y = mx+8 where you replace m with any real number.
You start with y = mx+b, and then replace the b with the y intercept 8.
The y intercept is where the polynomial crosses the y axis.
The value of m does not matter. So you could have y = 2x+8 or y = 3x+8 for instance. Replace m with whatever your favorite number is.
Answer:
Step-by-step explanation:
We see f(x) increase is linear and is 6 at each step, so m = 6 and y-intercept is b = -5, from point (0, -5)
<u>So the function is:</u>
Step-by-step explanation:
step 1. you mean which graph represents the equation y = (1/3)x + 2?
step 2. please provide the graphs - they are missing.
step 3. the equation has a slope of 1/3 which means it goes up one and three to the right.
step 4. the y intercept is 2 so it goes through the point (0, 2).
R^2=(x-6)^2+(y-4)^2
r^2=(6-2)^2+(4-1)^2, r^2=16+9=25
(x-6)^2+(y-4)^2=25
