Please help me solve this maths problem ☺

Mathematics

1 answer:

earnstyle [38]3 years ago

8 0

I cant see the image sorry man wish i could help

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Pls awnser these i dont understand them, like i beg u

Gekata [30.6K]

It’s not a good idea to beg

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2 years ago

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Why is the percent increase of 45 to 75 not equal to the percentage crease of 75 to 45 check all that apply.

nevsk [136]

Answer: B and F

Step-by-step explanation:

Since, In the first case original amount = 45

So, the increasing percentage when the original amount increases to 75,

= $\frac{75-45}{45} \times 100 = \frac{30}{45} \times 100= \frac{200}{3}$ %

In second case original amount = 75

So the decreasing percentage when the original amount decreases to 45,

= $\frac{75-45}{75} \times 100 = \frac{30}{75} \times 100= \frac{40}{1}$ %

Thus, We found that the ratio of the percent increase is not the same as the percent decrease ( because, $\frac{200}{3}\neq \frac{40}{1}$

Also, The original amount of the present increase is different from the original amount for the persons decrease. ( Because, $75\neq 45$

Therefore, Option B and F is correct only.

5 0

3 years ago

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Help pls :(<br><br><br> Solve for x.<br> -4 + 3x = 20

prohojiy [21]

$\huge\text{Hey there!}$

$\large\textsf{-4 + 3x = 20}\\\rightarrow\large\textsf{3x - 4 = 20}\\\\\large\text{ADD 4 to BOTH SIDES}\\\large\textsf{3x - 4 + 4 = 20 + 4}\\\large\text{CANCEL out: \textsf{-4 + 4} because that gives you \textsf 0}\\\large\text{KEEP: \textsf{20 + 4}} \text{ because it gives you the \textsf{x-value}}}\\\\\large\textsf{20 + 4 = \bf 24}\\\\\large\text{DIVIDE 3 to BOTH SIDES}\\\\\mathsf{\dfrac{3x}{3}= \dfrac{24}{3}}\\\large\text{CANCEL out: }\mathsf{\dfrac{3}{3}}\large\text{ because that gives you \textsf 1}$

$\large\text{KEEP: }\mathsf{\dfrac{24}{3}}\large\text{ because it helps gives you the result of the \textsf{x-value}}\\\\\mathsf{x = \dfrac{24}{3}}\\\\\large\textsf{x= 24}\div \large\textsf{3}}\\\large\textsf{x = \bf 8}\\\\\boxed{\boxed{\huge\text{Therefore, your answer is: \textsf{x = 8}}}}\huge\checkmark$