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elena-s [515]
3 years ago
13

Please help me solve this maths problem ☺

Mathematics
1 answer:
earnstyle [38]3 years ago
8 0
I cant see the image sorry man wish i could help

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he Statue of Liberty is approximately 305 feet tall. If the angle of elevation of a ship to the top of the statue is 22.9 degree
Andru [333]

Answer:

is at a distance of 722 feet

Step-by-step explanation:

we have the angle that forms between the water and the imaginary line between the ship and the tip of the statue

we have the statue height that would be the opposite leg to our angle and we want to know the distance of the ship to the statue that would be the adjacent leg

we see that it has (angle, adjacent, opposite)

well to start we have to know the relationship between angles, legas and the hypotenuse

a: adjacent

o: opposite

h: hypotenuse

sin α = o/h

cos α= a/h

tan α = o/a

it's the tangent

tan α = o/a

we replace the values ​​and solve

tan α = o/a

tan 22.9 = 305/a

a = 305/tan22.9

a = 305/0.4224

a = 722

is at a distance of 722 feet

7 0
3 years ago
Read 2 more answers
25
Elodia [21]

Answer:

33 degrees

Step-by-step explanation:

(4x+1) and (2x-19) add up to 180 degrees

(4x+1)+(2x-19)=180\\6x-18=180\\6x=198\\x=33

3 0
2 years ago
Is 1.7 rational or irrational
Tpy6a [65]

Answer:

rational

Step-by-step explanation:

5 0
3 years ago
Calculate the distance between the points M(6,2) and N(-1,7).
raketka [301]

Answer: chupapi munanyo

Step-by-step explanation:chupapi munanyo

8 0
3 years ago
Write the equation of each line using the given information.
Leni [432]

a) x – 2y + 6 = 0 b) x + y = 1 c) y = 1 d) y = -3x + 8

<h3><u>Solution:</u></h3>

<em><u>a. The points (-4,1) and (2,4) both lie on the line</u></em>

The general line equation on which (a, b) and (c, d) lies is:

y-\mathrm{b}=\frac{d-b}{c-a}(x - a)

Here the given points are (a, b) = (-4, 1) and (c, d) = (2, 4)

Thus the required equation is:

y-1=\frac{4-1}{2-(-4)}(x-(-4))

On solving we get,

\begin{array}{l}{\rightarrow y-1=\frac{3}{2+4}(x+4)} \\\\ {\rightarrow y-1=\frac{3}{6}(x+4)} \\\\ {\rightarrow 2(y-1)=1(x+4)} \\\\ {\rightarrow 2 y-2=x+4} \\\\ {\rightarrow x-2 y+6=0}\end{array}

<em><u>b.) m= -1 and the point (2, -1) lies on the line</u></em>

The equation of line in point slope form is y – b = m(x – a)  

where m is slope and (a, b) is a point on it

Here m = -1 and (a, b) = (2, -1)

Thus the required equation is:

y – (-1) = -1(x - 2)  

y + 1 = -x + 2  

y = -x + 2 -1  

y = -x + 1

<em><u>c. )It has the same slope as y = 5 and passes through (1, 1)</u></em>

our line has same slope with y = 5, then our equation would be y = k  and it passes through (x, y) = (1, 1) so, then by substitution

1 = k

k =1  

Then our equation will be y = k

y = 1

<em><u> d. ) m= -3 and it has a y-intercept of (0, 8)</u></em>

line equation in slope intercept form is y = mx + b where m is slope and b is y – intercept.

Then, our equation will be y = -3x + 8

We took y- intercept = 8 as it is the value of y when x = 0

6 0
3 years ago
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