The equations are as follow,
A) HCN (aq) + H₂O (l) ↔ H₂CN⁺ (aq) + OH⁻<span> (aq)
B) </span>H₂O (l) ↔ H⁺ (aq) + OH⁻ (aq)
C) HCN (aq) ↔ H⁺ (aq) + CN⁻ <span>(aq)
D) </span>HCN (aq) + H₂O (l) ↔ CN⁻ (aq) + H₃O⁺<span> (aq)
E) </span>HCN (aq) ↔ H⁻ (aq) + CN⁺<span> (aq)
Answer:
<u>Option-D </u>is the correct answer.
Explanation:
When hydrogen cyanide is added in water it partially ionizes as follow,
</span> HCN (aq) + H₂O (l) ↔ CN⁻ (aq) + H₃O⁺ (aq)
Being weak acid it fails to completely dissociate into H⁺ and CN⁻ ions. In this reaction water is acting as a Bronsted Lowery Base and picks proton from from HCN and converts into conjugate acid (i.e. H₃O⁺), while, HCN converts into conjugate Base (i.e. CN⁻).
Answer:
C
Explanation
Because My teacher told me that for an example Florida is hot but in Central America is cold or hot and you don’t need a jacket. I don’t remember much
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Answer:
Group B elements
Explanation:
Group B metals are referred to as transition metals. They are located in the middle of the periodic table between Group IIA and Group IIIA. They provide transition between the "base formers" on the left and "acid formers" on the right.