9! Direction: Create a K-W-H-L Chart (as seen below) and fill it to assess your prior knowledge and understanding of the topic.
1 answer:
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<u>Answer:</u> The unbalanced chemical equations are written below.
<u>Explanation:</u>
An unbalanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is not equal to the total number of individual atoms on the product side. These equations does not follow law of conservation of mass.
- <u>For a:</u>
The chemical equation for the reaction of nitrogen gas and oxygen gas follows:
The product formed is nitrogen dioxide.
- <u>For b:</u>
The chemical equation for the decomposition of dinitrogen pentaoxide follows:
The product formed is dinitrogen tetroxide and oxygen gas.
- <u>For c:</u>
The chemical equation for the reaction of ozone to oxygen gas follows:
The product formed is oxygen gas.
- <u>For d:</u>
The chemical equation for the reaction of chlorine and sodium iodide follows:
The product formed is sodium chloride and iodine gas
- <u>For e:</u>
The chemical equation for the reaction of magnesium and oxygen gas follows:
The product formed is magnesium oxide
The question is incomplete, the complete question is:
A certain liquid X has a normal freezing point of and a freezing point depression constant
. Calculate the freezing point of a solution made of 81.1 g of iron(III) chloride () dissolved in 850. g of X. Round your answer to significant digits.
<u>Answer:</u> The freezing point of the solution is
<u>Explanation:</u>
Depression in the freezing point is defined as the difference between the freezing point of the pure solvent and the freezing point of the solution.
The expression for the calculation of depression in freezing point is:
OR
......(1)
where,
Freezing point of pure solvent =
Freezing point of solution =
i = Vant Hoff factor = 4 (for iron (III) chloride as 4 ions are produced in the reaction)
= freezing point depression constant =
= Given mass of solute (iron (III) chloride) = 81.1 g
= Molar mass of solute (iron (III) chloride) = 162.2 g/mol
= Mass of solvent (X) = 850. g
Putting values in equation 1, we get:
Hence, the freezing point of the solution is