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qaws [65]
3 years ago
12

Polynomial Identities -The quadratic formula gives which roots for the equation......

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
8 0

Answer:

C

Step-by-step explanation:

The quadratic formula is x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}. Here a=2, b=1, and c=6.

Substitute and you'll have:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-1+/-\sqrt{1^2-4(2)(6)} }{2(2)}=\frac{-1+/-\sqrt{1+48} }{4)}

\frac{-1+/-\sqrt{1+48} }{4}=\frac{-1+/-\sqrt{49} }{4}=\frac{-1+/-7 }{4}= \frac{3}{2} , -2

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Peter started to deposit 5000 philippine pesos quarterly in a fund that pays 1% compounded interest. How much will be in the fun
gayaneshka [121]

Answer:

1. Answer: F = P123,514.09

Step-by-step explanation:

1. Peter started to deposit P5,000 quarterly in a fund that pays 1% compounded quarterly. How much will be in

the fund after 6 years?

1. Answer: F = P123,514.09

8 0
3 years ago
Help please! Calculate the exact value of cos (a-b) given that sin a= 12/13 with pi/2
zloy xaker [14]

Answer:

56/65

Step-by-step explanation:

First, we know that cos(a-b) = cos(a)cos(b) + sin(a)sin(b)

We know what sin(a) and sin(b) are, and to get cos(a), we can take the equation sin²a + cos²a = 1

Thus,

(12/13)² + cos²a = 1

1 - (12/13)² = cos²a

1- 144/169 = cos²a

cos²a = 25/169

cos(a) = 5/13

Similarly,

(3/5)² + cos²b = 1

1 - (3/5)² = cos²b

1 - 9/25 = cos²b

cos²b = 16/25

cos(b) = 4/5

Our answer is

cos(a-b) = cos(a)cos(b) + sin(a)sin(b)

cos(a-b)  = (5/13)(4/5) + (12/13)(3/5)

cos(a-b)  = 20/65 + 36/65

cos(a-b)  = 56/65

4 0
2 years ago
. Consumer Awareness In 1986, the average cost of a new midsize four-door sedan was $9000. In 1991, the average cost was $12,000
eduard

<u>Answer-</u>

\boxed{\boxed{y=9000(1.0592)^x}}

<em>And cost of a car in the year 2000 will be </em><em>$20134.18</em>

<u>Solution-</u>

Let's assume,

x = number of years after 1986

y = average cost of sedan in dollar

The exponential model that will model the scenario will be in the form of,

y=ab^x

where a and b are constants

As given that, in 1986 average cost of sedan was $9000 and in 1991 average cost of sedan was $12000

So, the points (0, 9000) and (5, 12000) will satisfy or lie on the exponential curve.

Putting (0, 9000) in the equation,

\Rightarrow 9000=ab^0

\Rightarrow a\times 1=9000

\Rightarrow a=9000

Now, the equation becomes y=9000b^x

Putting (5, 12000) in this equation,

\Rightarrow 12000=9000b^5

\Rightarrow b^5=\dfrac{12000}{9000}

\Rightarrow b=\sqrt[5]{\dfrac{4}{3}}

\Rightarrow b=1.0592

Putting the values,

y=9000(1.0592)^x

As we have to calculate the cost of sedan in 2000, so putting x=14(as 2000-1986=14),

y=9000(1.0592)^{14}=20134.18

Therefore, cost of a car in the year 2000 will be $20134.18

8 0
3 years ago
What is the solution to the equation One-fourth x + 2 = negative StartFraction 5 Over 8 EndFraction x minus 5?
ziro4ka [17]
Can you take a picture of the problem
8 0
3 years ago
Read 2 more answers
Is 3 decimeater less than 30 centimeters
koban [17]
3 decimeter is the same as 30 centimeters, because 1 decimeter=10 centimeter, so if you convert 3 decimeter into centimeters, you'll get 30, 3×10=30cm 

30cm=30cm, so your answer is both are equal. 
hope this helps...........

6 0
3 years ago
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