Perimeter is all sides added up together. So as you don't know a side's length you can put it as x and make an equation.
x + x + x + 6 + x + 6 = 180
4x +12 = 180
4x = 180 - 12
4x = 168
x = 168/4
x = 42
as length is 6 feet longer than width length is equal to 42 + 6 = 48 feet
By solving a system of equations, we will see that the width is 170ft and the length 275 ft.
<h3>
How to get the dimensions of the base?</h3>
For a rectangle of length x and width y, the perimeter is:
P = 2*(x + y).
Here we know that:
x = 2y - 65ft
p = 890ft = 2(x + y)
So we have a system of equations.
To solve this, we need to replace the first equation into the second one:
890ft = 2(x + y)
890ft = 2(( 2y - 65ft) + y)
Now we can solve this for y.
890ft = 4y - 130ft + 2y
890ft + 130ft = 6y
1020ft/6 = y = 170ft
So the width is 170ft, and we know that:
x = 2y - 65ft = 2*(170ft) - 65ft = 275ft
So the length is 275 ft.
If you want to learn more about systems of equations:
brainly.com/question/13729904
#SPJ1
Answer:
No, you cannot have the same input for 2 different outputs
Step-by-step explanation:
Ok for inequalities it's this < and > that so here's a example prob 3>2 so as my teacher used it put it "it's like the little number eats the bigger number." For negatives the one that's being eaten would be the one that's the closest to 0 so -3>-5 also alone way of doing this is to make a number line that's another way I was taught how to do these. I hope this helps you!
Answer:
Step-by-step explanation:
a) a^3-64b^3
=(a)^3-(4b)^3
=(a-4b)(a^2+4ab+16b^2)
b) 3x^3-81y^3z^6
=3(x^3-27y^3z^6)
=3{(x)^3-(3yz^2)^3}
=3(x-3yz^2)(x^2+3xyz^2+9y^2z^4)
c)16a^3b^3-54c^3d^3
=2(8a^3b^3-27c^3d^3)
=2{(2ab)^3-(3cd)^3
=2(2ab-3cd)(4a^2b^2+6abcd+9c^2d^2)
hope u got!!
