Simplify this expression. 3^-3
1 answer:
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Answer:
The observation would be considered unusual because it is farther than three standard deviations from the mean.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
When Z has an absolute value higher than 2, the observation is considered unusual.
In this problem, we have that:
So the correct answer is:
The observation would be considered unusual because it is farther than three standard deviations from the mean.
Hey!
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Question #1:
b + 0.6 = -1
b + 0.6 - 0.6 = -1 - 0.6
b = -1.6
Answer:
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Question #2:
y - 0.6 = -1.8
y + (-0.6) + 0.6 = 1.8 + 0.6
y = -1.2
Answer:
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Question #3:
n + 11.5 = -29
n + 11.5 - 11.5 = -29 - 11.5
n = -40.5
Answer:
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Question #4:
e - 14.4 = -20.8
e - 14.4 + 14.4 = -20.8 + 14.4
e = -6.4
Answer:
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Hope This Helped! Good Luck!