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Setler79 [48]
3 years ago
12

POSSIBLE

Mathematics
1 answer:
Nutka1998 [239]3 years ago
7 0
The answer to your problem is x=26
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Triangle HIJ has vertices H(1, 7) , I(−4, −2) , and J(−3, 5) . Write the coordinate notation for a translation of 3 units right
e-lub [12.9K]

Step-by-step explanation:

(x, y) -> (x+3, y+4)

that is what 3 units to the right (3 units into the outsource x direction) and 4 units up (4 units into the posits y directing) mean.

so, all points go through this translation

(1, 7) -> (4, 11)

(-4, -2) -> (-1, 2)

(-3, 5) -> (0, 9)

3 0
1 year ago
13. A packet of sweets costs $2.45.
Margaret [11]

Answer:

$2.45*4/7=$1.4

So felipe gets $1.4

Step-by-step explanation:

$2.45*4/7=$1.4

So felipe gets $1.4

4 0
3 years ago
The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
3 years ago
The following table shows the monthly defect rate for a product at a manufacturing company.
Lapatulllka [165]

Answer:

3

Step-by-step explanation:

3 0
2 years ago
Natasha packs a single layer of a prism with 5 cubes. Each cube measures 1 centimeter long on each edge. If 5 layers completely
Nastasia [14]

Answer:25

Step-by-step explanation

5 x 5 = 25. Got this problem correct on Imagine Math.

5 0
2 years ago
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