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Sonbull [250]
3 years ago
9

You put $600 in an account. The account earns $31 simple interest in 10 months. What is the annual interest

Mathematics
2 answers:
zepelin [54]3 years ago
8 0
The answer is $37.2 annually 
Ronch [10]3 years ago
4 0
45 is the answer because its right
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9. PRODUCTION Brown Pencil factory can
LuckyWell [14K]

Answer:

4500

Step-by-step explanation:

5 0
3 years ago
Attempted but just couldnt understand (25Points)​
Rashid [163]

Answer:

a) Function:Yes

b) Domain: -5\:

c) Range:  -5\le y\le 3

Step-by-step explanation:

The given graph passes vertical line test hence it is a function

The given function has x-intercepts at x=-4.5, x=-1,x=3.5

We can therefore write this function in factored form as y=a(2x+9)(x+1)(2x-7)

There is a y-intercept at (0,-2)

-2=a(2*0+9)(0+1)(2*0-7)

-2=-63a

a=\frac{2}{63}

The required function is

y=\frac{2}{63}(2x+9)(x+1)(2x-7)

b) The domain refers to all values of x for which this function is defined.

The domain from the graph is -5\: because there are holes at the end of the graph.

c) The range is the value of y for which x is defined or the graph exists.

From the graph the range is -5\le y\le 3

5 0
3 years ago
Two points on the graph of a function are used to determine the average rate of change over the interval between them. Calculate
dlinn [17]

Answer:

Step-by-step explanation:

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3 0
3 years ago
2y+8×=2 identify the table that would correctly graph this equation
lys-0071 [83]

We have

2y+8x=2

In order to obtain easily the table, we need to clear y

\begin{gathered} 2y=-8x+2 \\ y=\frac{-8x+2}{2} \\ y=-4x+1 \end{gathered}

then we evaluate for values of x

if x=0

y=-4(0)+1=1

y=1

if x=1

y=-4(1)+1=-3

y=3

if x=2

y=-4(2)+1=-7

y=-7

if x=3

y=-4(3)+1=-11

y=-11

So the table for the given equation is

x y

0 1

1 -3

2 -7

3 -11

3 0
1 year ago
Find all the complex roots. Write the answer in exponential form.
dezoksy [38]

We have to calculate the fourth roots of this complex number:

z=9+9\sqrt[]{3}i

We start by writing this number in exponential form:

\begin{gathered} r=\sqrt[]{9^2+(9\sqrt[]{3})^2} \\ r=\sqrt[]{81+81\cdot3} \\ r=\sqrt[]{81+243} \\ r=\sqrt[]{324} \\ r=18 \end{gathered}\theta=\arctan (\frac{9\sqrt[]{3}}{9})=\arctan (\sqrt[]{3})=\frac{\pi}{3}

Then, the exponential form is:

z=18e^{\frac{\pi}{3}i}

The formula for the roots of a complex number can be written (in polar form) as:

z^{\frac{1}{n}}=r^{\frac{1}{n}}\cdot\lbrack\cos (\frac{\theta+2\pi k}{n})+i\cdot\sin (\frac{\theta+2\pi k}{n})\rbrack\text{ for }k=0,1,\ldots,n-1

Then, for a fourth root, we will have n = 4 and k = 0, 1, 2 and 3.

To simplify the calculations, we start by calculating the fourth root of r:

r^{\frac{1}{4}}=18^{\frac{1}{4}}=\sqrt[4]{18}

<em>NOTE: It can not be simplified anymore, so we will leave it like this.</em>

Then, we calculate the arguments of the trigonometric functions:

\frac{\theta+2\pi k}{n}=\frac{\frac{\pi}{2}+2\pi k}{4}=\frac{\pi}{8}+\frac{\pi}{2}k=\pi(\frac{1}{8}+\frac{k}{2})

We can now calculate for each value of k:

\begin{gathered} k=0\colon \\ z_0=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{0}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{0}{2}))) \\ z_0=\sqrt[4]{18}\cdot(\cos (\frac{\pi}{8})+i\cdot\sin (\frac{\pi}{8}) \\ z_0=\sqrt[4]{18}\cdot e^{i\frac{\pi}{8}} \end{gathered}\begin{gathered} k=1\colon \\ z_1=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{1}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{1}{2}))) \\ z_1=\sqrt[4]{18}\cdot(\cos (\frac{5\pi}{8})+i\cdot\sin (\frac{5\pi}{8})) \\ z_1=\sqrt[4]{18}e^{i\frac{5\pi}{8}} \end{gathered}\begin{gathered} k=2\colon \\ z_2=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{2}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{2}{2}))) \\ z_2=\sqrt[4]{18}\cdot(\cos (\frac{9\pi}{8})+i\cdot\sin (\frac{9\pi}{8})) \\ z_2=\sqrt[4]{18}e^{i\frac{9\pi}{8}} \end{gathered}\begin{gathered} k=3\colon \\ z_3=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{3}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{3}{2}))) \\ z_3=\sqrt[4]{18}\cdot(\cos (\frac{13\pi}{8})+i\cdot\sin (\frac{13\pi}{8})) \\ z_3=\sqrt[4]{18}e^{i\frac{13\pi}{8}} \end{gathered}

Answer:

The four roots in exponential form are

z0 = 18^(1/4)*e^(i*π/8)

z1 = 18^(1/4)*e^(i*5π/8)

z2 = 18^(1/4)*e^(i*9π/8)

z3 = 18^(1/4)*e^(i*13π/8)

5 0
1 year ago
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