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sleet_krkn [62]
3 years ago
13

270 is ninety percent of what number ?

Mathematics
1 answer:
harina [27]3 years ago
6 0
The correct answer is 300.
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Belinda will earn $46,000 her first year working as an interior designer with annual raises of 10%. What are her total earnings
Musya8 [376]
I believe this is the answer

6 0
2 years ago
Suppose y = 48 + 3(2n - 1) is an explicit representation of an arithmetic sequence for integer values n ≥ 1. Find the xth partia
omeli [17]
a_n=48+3(2n-1)

The formula of the sum of the arithmetic sequence:
S_n=\dfrac{a_1+a__n}{2}\cdot n
calculate:
a_1=48+3(2\cdot1-1)=48+3=51
substitute
S_n=\dfrac{51+48+3(2n-1)}{2}\cdot n=\dfrac{99+6n-3}{2}\cdot n=\dfrac{96+6n}{2}\cdot n=3n^2+48n
Your answer is:
\boxed{f(x)=3x^2+48x}

5 0
3 years ago
Read 2 more answers
What are the first and last deciles of the standard Normal distribution?
aliya0001 [1]

My best Guess is

1.282 for upper . , -1.282 for lower.

Hope this Helps

-Dante

5 0
3 years ago
At a university, 60% of the 7,400 students are female. The student newspaper reports the results of a survey of a random sample
omeli [17]

Given Information:

Population mean = p  = 60% = 0.60

Population size = N = 7400

Sample size = n = 50

Required Information:

Sample mean = μ = ?

standard deviation = σ = ?

Answer:

Sample mean = μ = 0.60

standard deviation = σ = 0.069

Step-by-step explanation:

We know from the central limit theorem, the sampling distribution is approximately normal as long as the expected number of successes and failures are equal or greater than 10

np ≥ 10

50*0.60 ≥ 10

30 ≥ 10 (satisfied)

n(1 - p) ≥ 10

50(1 - 0.60) ≥ 10

50(0.40) ≥ 10

20 ≥ 10  (satisfied)

The mean of the sampling distribution will be same as population mean that is

Sample mean = p = μ = 0.60

The standard deviation for this sampling distribution is given by

\sigma = \sqrt{\frac{p(1-p)}{n} }

Where p is the population mean that is proportion of female students and n is the sample size.

\sigma = \sqrt{\frac{0.60(1-0.60)}{50} }\\\\\sigma = \sqrt{\frac{0.60(0.40)}{50} }\\\\\sigma = \sqrt{\frac{0.24}{50} }\\\\\sigma = \sqrt{0.0048} }\\\\\sigma =  0.069

Therefore, the standard deviation of the sampling distribution is 0.069.

4 0
2 years ago
What is the solution to -4 | -2x +6 | = -24
Norma-Jean [14]

Answer:

please ignore my answer

8 0
3 years ago
Read 2 more answers
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