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soldi70 [24.7K]
3 years ago
12

Evaluate 10-8(11+9)/16

Mathematics
2 answers:
eduard3 years ago
7 0

Answer:

\frac{5}{2}  \\

Step-by-step explanation:

\frac{10-8(11+9) }{16}  \\   = \frac{2(20)}{16}  \\  =  \frac{40}{16}  \\    =  \frac{5}{2}

goldfiish [28.3K]3 years ago
5 0

Answer:

0

Step-by-step explanation:

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Divide 1.20m in the ratio 2:3:4 in a clear way
tatuchka [14]
2:3:4 gives 9 equal parts.
1.20 divided by 9 is 0.133.

2 * 0.133 would be 0.266m
3 * 0.133 would be 0.399m
4 * 0.133 would be 0.533m

To check this calculate 0.533 + 0.399 + 0.266 would be 1.198m (close enough)
4 0
4 years ago
The class has collected $75.50 for a pizza party. A large pizza costs $9.50. Which one-step-inequality could be used to find the
Veseljchak [2.6K]

Answer:

7 large pizzas

Step-by-step explanation:

multiply 9.50 by every number on the calculator and get 9.50×7=66.5

or just divide 75.50 by 9.50

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4 0
3 years ago
Two rectangular prisms have the same volume. The area of the base of the blue prism is 216 square units. The area of the base of
valina [46]

Answer:

D)The height of the red prism is three times the height of the blue prism

Step-by-step explanation:

Here is the complete question

Two rectangular prisms have the same volume. The area of the base of the blue prism is 2 1/6 square units. The area of the base of the red prism is one third that of the blue prism.

which statement is true?

a)The height of the red prism is one-third the height of the blue prism

B)The height of the red prism is the same as the height of the blue prism

C)The height of the red prism is six times the height of the blue prism.

D)The height of the red prism is three times the height of the blue prism

Solution

Since both prisms have the same volume, V = A₁h₁ = A₂h₂ where A₁ and A₂ are the areas of the red and blue prisms respectively and h₁ and h₂ are the heights of the red and blue prisms respectively. For the question, A₁ = A₂/3. Substituting this into the equation, A₁h₁ = A₂h₂

A₂h₁/3 = A₂h₂

h₁ = 3h₂ . So the height of the red prism is thee times the height of the blue prism.

5 0
3 years ago
Read 2 more answers
Perimeter: 30 in<br> X <br> 13 in<br> 5 in
Julli [10]
Perimeter is adding up all the dues together
if it’s 30
13+5=18
30-18=12
x is 12
4 0
3 years ago
please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me
mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are  equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH=\sqrt{(5-0)^{2}+(1-1)^{2}}=5 and

GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5

Now, mid point of JH=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

=(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)

Mid point of GI=(\frac{5}{2},1)

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

(GI)^{2}=(IJ)^{2}+(JG)^{2}                             (1)

Now, JI=\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20} and GJ=\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}

Substituting these values in (1), we get

5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }

25=20+5

25=25

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5  and HJ=\sqrt{(0-5)^2+(1-1)^2}=5 are equal, thus, GHIJ is a rectangle.

6 0
3 years ago
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