Is there a picture to see from ?
x = 6 , 5
, − 3 IS THE ANSWER
Answer:
Solution given:
3(5x+8)
distribute
15x+8*3
<u>1</u><u>5</u><u>x</u><u>+</u><u>2</u><u>4</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u>
Answer:
Step-by-step explanation:
it is given that Square contains a chord of of the circle equal to the radius thus from diagram
![QR=chord =radius =R](https://tex.z-dn.net/?f=QR%3Dchord%20%3Dradius%20%3DR)
If Chord is equal to radius then triangle PQR is an equilateral Triangle
Thus ![QO=\frac{R}{2}=RO](https://tex.z-dn.net/?f=QO%3D%5Cfrac%7BR%7D%7B2%7D%3DRO)
In triangle PQO applying Pythagoras theorem
![(PQ)^2=(PO)^2+(QO)^2](https://tex.z-dn.net/?f=%28PQ%29%5E2%3D%28PO%29%5E2%2B%28QO%29%5E2)
![PO=\sqrt{(PQ)^2-(QO)^2}](https://tex.z-dn.net/?f=PO%3D%5Csqrt%7B%28PQ%29%5E2-%28QO%29%5E2%7D)
![PO=\sqrt{R^2-\frac{R^2}{4}}](https://tex.z-dn.net/?f=PO%3D%5Csqrt%7BR%5E2-%5Cfrac%7BR%5E2%7D%7B4%7D%7D)
![PO=\frac{\sqrt{3}}{2}R](https://tex.z-dn.net/?f=PO%3D%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7DR)
Thus length of Side of square ![=2PO=\sqrt{3}R](https://tex.z-dn.net/?f=%3D2PO%3D%5Csqrt%7B3%7DR)
Area of square![=(\sqrt{3}R)^2=3R^2](https://tex.z-dn.net/?f=%3D%28%5Csqrt%7B3%7DR%29%5E2%3D3R%5E2)
Area of Circle![=\pi R^2](https://tex.z-dn.net/?f=%3D%5Cpi%20R%5E2)
Ratio of square to the circle![=\frac{3R^2}{\pi R^2}=\frac{3}{\pi }](https://tex.z-dn.net/?f=%3D%5Cfrac%7B3R%5E2%7D%7B%5Cpi%20R%5E2%7D%3D%5Cfrac%7B3%7D%7B%5Cpi%20%7D)
Answer:
E(x) = 1.43 (Approx)
Step-by-step explanation:
Given:
Total number of camera = 7
Defective camera = 5
Sample selected = 2
Computation:
when x = 0
P(x=0) = 2/7 × 1/6 = 2/42
P(x=1) = [2/7 × 5/6] + [5/7 × 2/6] = 20/42
P(x=2) = 5/7 × 4/6 = 20/42
So,
E(x) = [0×2/42] + [1×20/42] + [2×20/42]
E(x) = 1.43 (Approx)