Answer:B is correct one
Step-by-step explanation:
You have to give more information
Answer:
<h2>
The mean decreases, and the median remains the same.</h2>
Step-by-step explanation:
Remember that a box plot is made by the quartiles of the distribution, the maximum value and the minimum value. So, from a box plot we can deduct the range, the median and the interquartile range.
In this case, the median remains the same at $9.5 per hour. The median is indicated by the middle line of the box, and you can observe that it doesn't change.
Now, the range of the data set decreases from 7 to 3.
On the other hand, the mean must decrease, because data greater than $11 doesn't exist in the box plot number 2, and the mean is a central measure sensible to those changes.
Therefore, the right answer is <em>The mean decreases, and the median remains the same.</em>
Answer:
0.18203 = 18.203% probability that exactly four complaints will be received during the next eight hours.
Step-by-step explanation:
We have the mean during a time-period, which means that the Poisson distribution is used to solve this question.
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
A service center receives an average of 0.6 customer complaints per hour.
This means that
, in which h is the number of hours.
Determine the probability that exactly four complaints will be received during the next eight hours.
8 hours means that
.
The probability is P(X = 4).


0.18203 = 18.203% probability that exactly four complaints will be received during the next eight hours.