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ycow [4]
3 years ago
14

Deva bought 9 1/2 m of cloth for rupees 28 1/2.Samruth buys 26 1/3 m of same cloth. how much should samruth pay the shopkeeper?

Mathematics
1 answer:
likoan [24]3 years ago
5 0

For this case we can make the following rule of three:

9 1/2 m --------------> 28 1/2 rupees

26 1/3 m -------------> x

From here, we clear the value of x.

We have then:

x = (\frac{26+\frac{1}{3}}{9+\frac{1}{2}}) (28+\frac{1}{2})

Rewriting we have:

x = (\frac{\frac{79}{3}}{\frac{19}{2}}) (\frac{57}{2})

x = (\frac{158}{57}) (\frac{57}{2})

x = \frac{158}{2}

x = 79

Answer:

samruth should pay 79 rupees to the shopkeeper

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3 years ago
A real estate agent has 17 properties that she shows. She feels that there is a 50% chance of selling any one property during a
Likurg_2 [28]

Answer:

0.0011 = 0.11% probability of selling less than 3 properties in one week.

Step-by-step explanation:

For each property, there are only two possible outcomes. Either they are sold, or they are not. The chance of selling any one property is independent of selling another property. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A real estate agent has 17 properties that she shows.

This means that n = 17

She feels that there is a 50% chance of selling any one property during a week.

This means that p = 0.5

Compute the probability of selling less than 3 properties in one week.

This is

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{17,0}.(0.5)^{0}.(0.5)^{17} \approx 0

P(X = 1) = C_{17,1}.(0.5)^{1}.(0.5)^{16} = 0.0001

P(X = 2) = C_{17,2}.(0.5)^{2}.(0.5)^{15} = 0.0010

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0.0001 + 0.0010 = 0.0011

0.0011 = 0.11% probability of selling less than 3 properties in one week.

5 0
3 years ago
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