The orthocenter is the point where the three altitudes meet.
sketch the graph and you will see that AB is a horizontal line, the altitude is a vertical line through the point (1,3), so the equation of this altitude is x=1
next, find another altitude. I'll use the altitude of BC.
the slope of BC is (6-3)/(4-1)=1, so the slope of the altitude, which is perpendicular to BC going through the point A (0,6), is -1, the equation of the altitude of BC is y=-x+6
the system of equation : x=1
y=-x+6
has a solution (1, 5)
the solution is where the two lines meet, the meeting point is the orthocenter.
Double check by find the equation for other altitude:
slope of AC: (3-6)/(1-0)=-3
slope of altitude of AC: 1/3
equation of altitude of AC: y=(1/3)x+b
the altitude of AC goes through point B (4,6), so we can find out b by plug x=4, y=6 in the equation: 6=(1/3)*4+b, b=14/3
y=(1/3)x+14/3
Is (1,5) also a solution to this equation? Plug x=1 in the equation, we get y=5, so yes, (1,5) is a point on the third altitude.
Answer:
63.2
Step-by-step explanation:
Corresponding sides of similar triangles are proportional, so
Answer:
28...?
Step-by-step explanation:
Well, the question states that Martin has 28 basketball cards at the start of the question, and asks how many he has at the end. Martin still has 28 cards. Unless part of the question was cut, then this is your answer.
y=-x
slope for perp line = 1
2y=-x+6
y=-1/2x +3
slope for perp line = 2
15.
i don’t wanna do all sorry it’s a lot of work so i’ll tell u how to do it instead. first write it in slope intercept form which is
y-y1=m(x-x1)
it’s parallel which means it shares the same slope. if it’s perpendicular it would be opposite reciprocals so for -3/2 the perp slope would be 2/3.
the line is
y+1=3/4(x-4)
we distribute the 3/4 so it’s now
y+1=3/4x-3
then we subtract the 1
y=3/4x-4 is the equation boom done
