Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Range is 1 because they all go up by 1
Simplify, <em>7(2x+y)+6(x+5y).</em>
<em>a:</em> <em>20x+37y</em>
<em> (7 • (2x + y)) + 6 • (x + 5y)
</em>
<em>Step 2 :
</em>
<em>Equation at the end of step 2 :
</em>
<em> 7 • (2x + y) + 6 • (x + 5y)
</em>
<em>Step 3 :
</em>
<em>Final result :
</em>
<h3><em> </em>
<em> 20x + 37y</em></h3>
Thanks,
<em>Deku ❤</em>
Answer:
1/1024
Step-by-step explanation:
1/(4*4*4*4*4)
1/1024
Answer:
6√10
Step-by-step explanation:
factorizing 6 and 60
6 = 2 x 3
60 = 2 x 2 x 3 x 5
hence
√6 · √60
= √ [ (2 x 3) · (2 x 2 x 3 x 5) ]
= √ (2· 2² · 3² · 5)
= √ (2² · 3²) x √(2·5)
= (2 · 3) x √10
= 6√10