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3 years ago

What is the answer for this question please

Mathematics

2 answers:

Hunter-Best [27]3 years ago

4 0

The answer is 3 bc i used a book

Zigmanuir [339]3 years ago

3 0

Answer:

Step-by-step explanation:

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Express p as the subject of the formula q= p² - r ÷ t

Rudik [331]

Answer:

p = $\sqrt{q +\frac{r}{t} }$

Step-by-step explanation:

q= $p^{2}$ - r÷ t using BODMAS

q = $p^{2}$ - (r/t)

q + r/t = $p^{2}$

p= $\sqrt{q+\frac{r}{t} }$

7 0

3 years ago

SOMEONE PLEASE JUST ANSWER THIS FOR BRAINLIEST!!’

ad-work [718]

Factoring this expression using the identity of a²-b² = (a+b)(a-b)

Given :-

25 - x²

This can be broken down into:-

... ( 5 )² - ( x )²

In this case, a is 5 and b is x

... ( 5 + x ) ( 5 - x ) Is the answer.

Hope it helps!!

7 0

3 years ago

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Which expression is equivalent to 36÷3+3?

Igoryamba

Answer:

36÷6

Step-by-step explanation:

3+3 = 6

-kiniwih426

5 0

3 years ago

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Solve, please!!!!!! I really need this!!!

finlep [7]

Just go to math papa. It solves all kinds of problems like these. Anyways the answer is a=4. Please give me a thanks.

8 0

4 years ago

Read 2 more answers

Please help! Would be appreciated so much

Cloud [144]

Answer:

25%.

Step-by-step explanation:

First, let's find the area of both circles. The area of a circle is given by:

$\displaystyle A = \pi r^2$

The radius of the smaller circle is one. Thus, its area is:

$\displaystyle A = \pi (1)^2 = \pi$

The radius of the larger circle is two. Thus, its area is:

$\displaystyle A = pi (2)^2 = 4\pi$

The probability that a random point chosen will be inside the small circle will be the area of the small circle over the total area. Hence:

$\displaystyle P= \frac{\pi }{4\pi}=\frac{1}{4}= 25\%$

The probability of a random point being in the small circle is 25%.

3 0

3 years ago