State the vertex and axis of symmetry of the graph of y=ax^2+c
General form of quadratic equation is
There is no bx in our given equation, so we put 0x
Given equation can be written as
a=a , b=0
Now we use formula to find vertex
Now we plug in 0 for 'a' and find out y
So our vertex is (0,c)
The axis of symmetry at x coordinate of vertex
So x=0 is our axis of symmetry
Answer:
An equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12 will be:
Step-by-step explanation:
Given the equation
converting the line into the slope-intercept form y = mx+b, where m is the slope
The slope of the line = m = 5
We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:
Therefore, the slope of new line = – 1/m = -1/5 = -1/5
Using the point-slope form of the line equation
where m is the slope of the line and (x₁, y₁) is the point
substituting the slope of new line = -1/5 and (-2, 3)
Add 3 to both sides
Therefore, an equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12 will be: