Answer:
Step-by-step explanation:
this is exactly the same as the 1st one, just they put it in a different orientation. sooo use law of cosines , where
QR = c
a = 12
b = 23
cos(120) = cos (P)
c = sq rt [ a^2+b^2﹣2*a*b*cos(P) ]
QR = sq rt [ 12^2 + 23^2 - 2* 12*23*cos(120) ]
QR = sq rt [ 144 + 529 - 552 * (-0.5 0 ]
QR = sq rt [ 673 + 276 ]
QR = sq rt [ 949 ]
QR = 30.8058
rounded to nearest 10th is
QR = 30.8 :)
Here is the answer from SparkNotes
http://www.sparknotes.com/math/algebra2/operationsonfunctions/section3.rhtml
Answer:
20 square units
Step-by-step explanation:
B * H
height = 5
base = 4
4 * 5
20
What is the question for the problem are you trying to figure out area or perhaps perimeter and of what the shaded or non shaded next time include that in your answer.
11.7
Formula: a^2 + b^2 = c^2
so substitute the numbers like this:
10^2 + 6^2 = c^2
both 10^2 and 6^2 are perfect squares:
10 × 10= 100 and 6 × 6= 36
100 + 36= c^2
add:
100 + 36 =
136 = c^2
now in order to get rid of the squared, you put it into a radical:
√136 = √c^2
note: whatever you do on one side, you do to the other
it's easier to use the calculator for this so put √136 and you're gonna get 11.66
since it's asking you to round it to the nearest tenth:
11.66 = 11.7
sorry if the explanation is kinda long ✋ i tried explaining it better in the end but i failed
