Answer:
A
Explanation:
I know this because I just took the test and got it right.
Let’s assume a wire-hair terrier is a true breed for wire hair with alleles (BB) and a smooth-hair terrier is true breed for smooth hair (bb). Allele B is dominant over its allele b. When these two terrier mated and produce offspring wire-hair terrier and smooth-hair terrier in the ratio 3:1.
Based on this result it can be inferred that –
a. The pattern of inheritance is monohybrid cross.
b.Genotype of wire-hair terrier (1BB and 2 Bb) and genotype of smooth-hair terrier is (bb)
c. Phenotype ratio will be 3:1 and genotypic ratio will be 1:2:1.
Hey, there! The correct answer to this question will be D. Acris crepitans.
<span> They can be classified according to the core structural functional groups' locations as </span><span>alpha- (α-), beta- (β-), gamma- (γ-) or delta-(δ-)</span><span> amino acids; other categories relate to </span>polarity<span>, </span>pH<span> level, and side-chain group type (</span>aliphatic<span>, </span>acyclic<span>, </span>aromatic, containing hydroxyl orsulfur<span>, etc.). In the form of </span>proteins<span>, amino acids comprise the second-largest component (water is the largest) of human </span>muscles<span>, </span>cells<span> and other </span>tissues.[5]<span> Outside proteins, amino acids perform critical roles in processes such as </span>neurotransmitter<span> transport and </span>biosynthesis<span>.</span>
