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Ede4ka [16]
3 years ago
7

A man gave half of his welfare allowance to his wife,1/5 to each of his two sons the rest to his daughter. Find the fraction giv

en to the daughter.​
Mathematics
1 answer:
vichka [17]3 years ago
8 0

Answer:

1/10.

Step-by-step explanation:

Total allowance=1

Half to wife so 1-1/2=1/2(Left from total)

1/5 to each son so 2/5 to both(Total for sons).

Left for daughter 1/2-2/5=1/10(Ans)

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A warehouse employs 22 workers on first shift and 18 workers on second shift. Eight workers are chosen at random to be interview
bogdanovich [222]

Answer:

The probability is 0.0042

Step-by-step explanation:

The probability is the division between the number of ways in which the eight workers are chosen from the first shift and the total number of ways in which they can select the eight workers.

So,  the number of ways in which the eight workers are chosen from the first shift is calculate using the following equation:

nCk=\frac{n!}{k!(n-k)!}

Where nCk give as the number of ways in which we can select k element from a group of n elements.

Then replacing k by the eight workers that are going to do the interview and n by the 22 workers from the first shift we get:

22C8=\frac{22!}{8!(22-8)!}= 319,770

So there are 319,770 ways to select eighth workers and all of them are first shift workers.

At the same way, we can calculate the total number of ways in which they can select the eight workers. Replacing n by 40 because this is the sum of 22 workers of the first shift and 18 workers of the second shift, we get:

40C8=\frac{40!}{8!(40-8)!}= 76,904,685

So, There are 76,904,685 ways to select eight workers from a group of 40.

Finally the probability is:

\frac{22C8}{40C8} = \frac{319,770}{79,904,685} =0.0042

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