A man gave half of his welfare allowance to his wife,1/5 to each of his two sons the rest to his daughter. Find the fraction giv
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The given sequence is
a₁ = 29
a₂ = 39
a₃ = 49
a₄ = 59
This sequence is an arithmetic sequence. Th first term is a₁ = 29, and the common difference is d= 10.
The n-th term is
The 33-rd termis
a₃₃ = 29 + (33 - 1)*10
= 29 + 320
= 349
Answer: a₃₃ = 349
a₁ = 29
a₂ = 39
a₃ = 49
a₄ = 59
This sequence is an arithmetic sequence. Th first term is a₁ = 29, and the common difference is d= 10.
The n-th term is
The 33-rd termis
a₃₃ = 29 + (33 - 1)*10
= 29 + 320
= 349
Answer: a₃₃ = 349
Answer:
Step-by-step explanation:
We know that , the equation of a line that passes through (a,b) and (c,d) is given by :_
Standard form of equation of line =
Given points = (7, -3) and (4, -8)
Then, the equation of a line that passes through the points . (7, -3) and (4, -8) is given by -
[∵ (-)(-)=(+)]
Or
Hence, the required equation :-