30/4-3/4= 27/4
..........................
check the picture below.
![\bf tan(22^o)=\cfrac{x}{80}\implies \boxed{80tan(22^o)=x} \\\\[-0.35em] ~\dotfill\\\\ tan(43.5^o)=\cfrac{y+x}{80}\implies 80tan(43.5^o)=y+x\implies 80tan(43.5^o)-x=y \\\\\\ 80tan(43.5^o)-80tan(22^o)=y\implies 43.59506727037783689501 \approx y \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{rounded~up}{44=y}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20tan%2822%5Eo%29%3D%5Ccfrac%7Bx%7D%7B80%7D%5Cimplies%20%5Cboxed%7B80tan%2822%5Eo%29%3Dx%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A~%5Cdotfill%5C%5C%5C%5C%0Atan%2843.5%5Eo%29%3D%5Ccfrac%7By%2Bx%7D%7B80%7D%5Cimplies%2080tan%2843.5%5Eo%29%3Dy%2Bx%5Cimplies%2080tan%2843.5%5Eo%29-x%3Dy%0A%5C%5C%5C%5C%5C%5C%0A80tan%2843.5%5Eo%29-80tan%2822%5Eo%29%3Dy%5Cimplies%2043.59506727037783689501%20%5Capprox%20y%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A~%5Chfill%20%5Cstackrel%7Brounded~up%7D%7B44%3Dy%7D~%5Chfill)
make sure your calculator is in Degree mode.
27k -6 is equal to 3(9k - 2 )
and 5x +60 is equal to 5(x + 12) :)))
i hope this is helpful
have a nice day
f(5) = 3 means (5,3) is on the graph of f.
On the new graph, y = f(x+1) + 2, what do the +1 and +2 do?
Things inside the function notation inpact the x-values, since that's where x sits.
This outside the f(x) notation impact the y-values, since those are done after you've evaluated the function.
"+1" on the inside shifts every point to the left 1 unit. (Inside changes are almost always opposite from what it looks like it would do.)
"+2" on the outside will shift every point up by 2 units.
So what do you get if you take (5,3) and shift it left 1 and up 2?
