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Bond [772]
3 years ago
13

X is a positive integer and 15x - 43 < 5x + 2. Work out the possible values of x.​

Mathematics
1 answer:
Mice21 [21]3 years ago
5 0

Answer:

x = 1, 2, 3, 4

Step-by-step explanation:

15x - 43 < 5x + 2

15x - 5x - 43 < 2

15x - 5x < 2 + 43

10x < 45

x < 4.5

x = 1, 2, 3, 4

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Brendan has 33 coins in his pocket, all of which are dimes and quarters. if the total value of his change is 615 cents, how many
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If all were dimes, the value would be $3.30. Brendan has $2.85 more than that. Each quarter that replaces a dime increases the value by $0.15, so Brendan must have $2.85/$0.15 = 19 quarters.

Brendan has 14 dimes and 19 quarters.
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2 years ago
Can somebody help me I’m stuck with this!!
Mama L [17]
I believe it’s A, C, and E
3 0
3 years ago
B. If instead you divide first to solve the equation, what<br> operation would you need to use last?
Sedbober [7]

Answer:

use  PEDMAS

P: PARENTHESIS

E: EXPONENTS

D: DIVISON

M: MULTIPLICATION

A: ADDITION

S: SUBTRACTION

Step-by-step explanation:

CAN YOU PLS MARK ME BRAINLIEST THANK YOU !

8 0
2 years ago
WILL GIVE BRAINLIEST
NemiM [27]
15, 18, 21

i don't know the other one, sorry
6 0
3 years ago
Read 2 more answers
Help 3 and 4 please!!!!!!!!!!!!
aleksandrvk [35]
Easy peasy

the bit where it says
D={something}
those are the numbers you should input for x to get y values


3.
first solve for y to make life easier
-3x-5y=20
times -1
3x+5y=-20
minus 3x both sides
5y=-3x-20
divide both sides by 5
y=-3/5x-4
sub value of the domain
x=-10
y=-3/5(-10)-4
y=6-4
y=2
a point is (-10,2)

x=-5
y=-3/5(-5)-4
y=3-4
y=-1
(-5,-1) is another

x=0
y=-3/5(0)-4
y=-4
(0,-4) is another

x=5
y=-3/5(5)-4
y=-3-4
y=-7
(5,-7)

points are (-10,2), (-5,-1), (0,-4), (5,-7)



4.
input
x=-2
y=(-2)^2-3
y=4-3
y=1
(-2,1)

x=-1
y=(-1)^2-3
y=1-3
y=-2
(-1,-2)

x=0
y=(0)^2-3
y=-3
(0,-3)

x=1
y=(1)^2-3
y=1-3
y=-3
(1,-3)

x=2
y=(2)^2-3
y=4-3
y=1
(2,1)

the points are (-2,1), (-1,-2), (0,-3), (1,-2), (-2,1)

see graph below

5 0
2 years ago
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