This is a linear differential equation of first order. Solve this by integrating the coefficient of the y term and then raising e to the integrated coefficient to find the integrating factor, i.e. the integrating factor for this problem is e^(6x).
<span>Multiplying both sides of the equation by the integrating factor: </span>
<span>(y')e^(6x) + 6ye^(6x) = e^(12x) </span>
<span>The left side is the derivative of ye^(6x), hence </span>
<span>d/dx[ye^(6x)] = e^(12x) </span>
<span>Integrating </span>
<span>ye^(6x) = (1/12)e^(12x) + c where c is a constant </span>
<span>y = (1/12)e^(6x) + ce^(-6x) </span>
<span>Use the initial condition y(0)=-8 to find c: </span>
<span>-8 = (1/12) + c </span>
<span>c=-97/12 </span>
<span>Hence </span>
<span>y = (1/12)e^(6x) - (97/12)e^(-6x)</span>
Answer:
23
Steps ig
((8x2) +2x(-3)))-(((-(-4)) x 2) +( 3 x( -7)) =23
Try 8, 7, 4, 1 (I believe that’s the right answer but I’m not sure)
Answer:
x > -3.2
Step-by-step explanation:
Answer:
50000 times
Step-by-step explanation:
Since these are given in scientific notation, we can convert them to have the same powers of 10. Converting 4*10^12 to something times 10^7, we can get 4*10^5*10^7. So we divide 400000 by 8 to see how many times larger it is than 8. So we get 50000 times as our answer.
