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2 years ago

Please could someone help

Mathematics

1 answer:

Zolol [24]2 years ago

3 0

Answer:

x ≈ -0.90, y ≈ 2.31

x ≈ 1.40, y ≈ 9.19

Step-by-step explanation:

Easiest and fastest way to do this is to graph the systems of equations and trace where the graphs intersect:

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Hello, can anyone help, please?

vazorg [7]

Answer: dude you can do this yourself.

Step-by-step explanation:

toss coins ;-;

6 0

2 years ago

You are saving money to buy an electric guitar. You deposit $1000 in an account that earns interest compounded annually. The exp

Katena32 [7]

Let's move like a crab, backwards some.

after 2 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &2
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 2}\implies A=1000(1.03)^2$

after 3 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &3
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3$

is that enough to pay the $1100?

now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000 <---- standard form.

8 0

2 years ago

Let f(x) = ............

34kurt

Answer:

So first lets find g(-1)

so we plug in the answers:

-2 * -1 ^2 -4

-2*1-4 = -2-4 =

-6

Now lets solve for f(-2)

-2^2-3

4-3=1

-6+1 = 5

3*5 = 15

Im getting answer of 15 but it shows -15 or something, so I dont know if I got it wrong or if its like a dash then the answer.

3 0

3 years ago

Work out the area of this quarter circle of radius 8 cm. Give your answer in terms of pie

Bess [88]

16pi

Step-by-step explanation:

pi x r² = ans ÷ 4 = Answer for area

Pi×8²=64pi ÷ 4 = 16pi

3 0

3 years ago

The function f(x)=-(x-3)^2 +9 can be used to represent the area of a rectangle with the perimeter of 12 units, as a function of

Ivenika [448]

Maximum area of the rectangle is $9cm^{2}$

Explanation:

Considering the dimensions to be in cm

$f(x) = -(x-3)^{2} +9\\f(x) = -(x^{2} +9 - 6x)+9\\f(x) = -x^{2} +6x\\f'(x) = -2x+6\\-2x+6 = 0\\2x=6\\x=3cm\\\\$

Putting the value of x = 3

$Perimeter = 2(x+b)\\12 = 2(3+b)\\6 = 3+b\\b= 3cm$

$Area of rectangle = x X b\\ = 3 X 3\\ = 9cm^{2}$

Therefore, maximum area of the rectangle is $9cm^{2}$

7 0

2 years ago