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tangare [24]
2 years ago
10

How do I simplify this?

Mathematics
1 answer:
elena-14-01-66 [18.8K]2 years ago
6 0
Combine like terms

5) = 4
8) = -5a -12
11) = 4b - 6

hope it helps
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The distance between Cincinnati, Ohio and Charlotte, North Carolina is about 336 miles. The distance between Cincinnati and Chic
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Check the picture below, bear in mind that all 3 cities are colinear.

\bf \stackrel{\textit{Charlotte to Chicago}}{336+247}+\stackrel{\textit{Chicago to Cincinnat} i}{247}

4 0
3 years ago
Please help this is due in like 20 minutes
bearhunter [10]

Answer:

cant see the attatchment clearly can you pls try resubmitt

Step-by-step explanation:

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3 years ago
Suppose a researcher is conducting a hypothesis test for a mean and finds a test statistic of z=2.3z=2.3 . Which of the choices
Galina-37 [17]

Answer:

Option c. The result is significant at the 0.020.02 level.

Step-by-step explanation:

We are given the following in the question:

We are conducting a one tailed hypothesis test with alternate hypothesis

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The z test calculated for the same is

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We calculate the p-value from the standard normal table.

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The result is not significant

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The result is significant at 0.02 significance level.

Thus, the correct answer is

Option c. The result is significant at the 0.020.02 level.

3 0
2 years ago
There are five questions listed below. Each question includes the quantity 43. Match the 43 in each question on the left to
stellarik [79]

Answer:

Step-by-step explanation:

What number is 15% of 43?

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43% of 300 is what number?

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12% of what number is 43?

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43 is what percent of 106?

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What percent of 43 is 6?

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3 0
2 years ago
You deposit $7550 in an account that pays 7.25% interest, compounded continuously. How long to the
Afina-wow [57]

~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$\stackrel{tripled}{(7550)3}\\ P=\textit{original amount deposited}\dotfill & \$7550\\ r=rate\to 7.25\%\to \frac{7.25}{100}\dotfill &0.0725\\ t=years \end{cases}

3(7550)=7550e^{0.0725\cdot t}\implies \cfrac{3(7550)}{7550}=e^{0.0725t}\implies 3=e^{0.0725t} \\\\\\ \log_e(3)=\log_e\left( e^{0.0725t} \right)\implies \ln(3)=0.0725t \\\\\\ \cfrac{\ln(3)}{0.0725}=t\implies 15.15327\approx t\implies 15\approx t

7 0
2 years ago
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