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3 years ago

What is the Awnser to this?

Mathematics

1 answer:

pickupchik [31]3 years ago

8 0

The answer is 16 and 3

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Diya used modeling to find

slamgirl [31]

Answer:C

Step-by-step explanation: The quotient is correct because 27 tenths divided by 3 is 0.9 and 12 hundredths divided by 3 is 0.04

8 0

2 years ago

shayla has a number cube that is number to 6 there is a different number on each side of the cube if shawls rolls the cube 50 ti

Orlov [11]

Answer: 8.33 times

Explanation:

P(4) = 1/6

P(4) for 50 times = 1/6 x 50 = 8.33 times

4 0

3 years ago

B. Now, assume that all of these circles have a radius of two. Then, calculate the ratio of a proximate circumference to the dia

Alenkasestr [34]

Answer:

I think b is the answer hopefilly

5 0

2 years ago

Read 2 more answers

Luego de su cumpleaños, Benjamín ha decidido donar la tercera parte del dinero que recibió de regalo de sus familiares a una fun

Aloiza [94]

Answer:

The dependent variable is the amount of money he received for birthday.

Step-by-step explanation:

After his birthday, Benjamin has decided to donate a third of the money he received as a gift from his relatives to a foundation. Considering the variables amount of money received by Benjamin and amount of money that Benjamin will donate. to. What is the dependent variable in this situation.

Here, the money he received for the birthday is x.

So, he donated x/3.

The variable is the money which he gets, so the dependent variable is amount of money he received for the birthday.

3 0

2 years ago

The following describes a sample. The information given includes the five number summary, the sample size, and the largest and s

lys-0071 [83]

Answer:

$L= Q_1 - 1.5*IQR = 210 -1.5*40 =150$

$U= Q_3 + 1.5*IQR = 250 +1.5*40 =310$

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

Step-by-step explanation:

For this case we have the 5 number summary

(160,210,220,250,270)

So then we have:

minimum = 160 , Q1 = 210, Q2= Median=220, Q3 = 250, Max=270

If we find the interquartile range we got:

$IQR = Q_3 -Q_1 = 250-210 =40$

For this case we need to find the lower and upper limit with the following formulas:

$L= Q_1 - 1.5*IQR = 210 -1.5*40 =150$

$U= Q_3 + 1.5*IQR = 250 +1.5*40 =310$

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

4 0

3 years ago