All categories

3 years ago

This graph shows a proportional relationship. What is the constant of proportionality?

Mathematics

1 answer:

allsm [11]3 years ago

4 0

Answer:

$m = \frac{3}{4}$

Step-by-step explanation:

Given

See attachment

Required

The constant of proportionality

Select two points on the graph

$(x_1,y_1) = (0,0)$

$(x_2,y_2) = (4,3)$

So, the constant of proportionality (k) is:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{3-0}{4-0}$

$m = \frac{3}{4}$

You might be interested in

What is the sum of 6 7/8+4 5/8 =?

lianna [129]

The answer is 11 1/2
Hoped that helped

4 0

3 years ago

Read 2 more answers

You take a taxi to your sisters home. The driver charges you $8 for 3 kilometers and $2 for each additional kilometer. If you pa

vivado [14]

14-8=6. So far we have 3 km, then 6 divided by 2 which is 3 additional kilometers. 3+3 is 6 so the final answer is 6km

7 0

3 years ago

Read 2 more answers

At the beginning of this year, you went out and purchased $300 worth of gold coins. Every 3 months for the next 8 years, you pur

Lunna [17]

Answer:

9900

Step-by-step explanation:

You start with 300, and add 300 32 times (once for every 3 months in 8 years).

$300+9600=9900$

7 0

2 years ago

What is the fully simplified answer to sqrt(7/18) + sqrt(5/8) - sqrt(7/2)

NeX [460]

Answer:

$=\frac{-4\sqrt{7}+3\sqrt{5}}{6\sqrt{2}}$

Step-by-step explanation:

Given expression as:

$=\sqrt{\frac{7}{18}}+\sqrt{\frac{5}{8}}-\sqrt{\frac{7}{2} }$

We need to simplify the given expression.

Solution:

We have:

$=\sqrt{\frac{7}{18}}+\sqrt{\frac{5}{8}}-\sqrt{\frac{7}{2} }$

Rewrite the expression as:

$=\frac{\sqrt{7}}{3\sqrt{2}} - \frac{\sqrt{7}}{\sqrt{2}} +\frac{\sqrt{5}}{2\sqrt{2}}$

$\frac{\sqrt{7}}{\sqrt{2} }$ is a common factor to the first two terms.

Using distributive property we can factor out $\frac{\sqrt{7}}{\sqrt{2} }$ from the first two terms.

$=\frac{\sqrt{7}}{\sqrt{2}}(\frac{1}{3} -1) +\frac{\sqrt{5}}{2\sqrt{2}}$

$=\frac{\sqrt{7}}{\sqrt{2}}(\frac{1-3}{3}) +\frac{\sqrt{5}}{2\sqrt{2}}$

$=\frac{\sqrt{7}}{\sqrt{2}}(\frac{-2}{3}) +\frac{\sqrt{5}}{2\sqrt{2}}$

$=-\frac{2\sqrt{7}}{3\sqrt{2}} +\frac{\sqrt{5}}{2\sqrt{2}}$

$\sqrt{2}$ is common factor, so we can factor $\sqrt{2}$ from the above expression.

$=\frac{1}{\sqrt{2} }( -\frac{2\sqrt{7}}{3} +\frac{\sqrt{5}}{2})$

$=\frac{1}{\sqrt{2} }( \frac{-2\times 2\sqrt{7}+3\times \sqrt{5}}{6})$

$=\frac{1}{\sqrt{2} }( \frac{-4\sqrt{7}+3\sqrt{5}}{6})$

$=\frac{-4\sqrt{7}+3\sqrt{5}}{6\sqrt{2}}$

Therefore, we get simplified answer as.

$=\frac{-4\sqrt{7}+3\sqrt{5}}{6\sqrt{2}}$

6 0

4 years ago

Here are 10 test scores: 30, 74, 76, 77, 78, 79, 80, 80, 82, 84. The mean of these scores is 74.

creativ13 [48]

We add up all those numbers (excluding 30) and divide by the number of numbers (9). This results in 78.8 (round up to 79).

79-74 = 5. So the mean has increased by 5 points. (C)

8 0

3 years ago