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pochemuha
3 years ago
15

Write the standard form of the line that contains a slope of 2/3 and passes through the point (1,1). Include your work in your f

inal answer. Type your answer in the box provided or use the upload option to submit your solution.
Mathematics
1 answer:
Simora [160]3 years ago
8 0

Answer:

2x - 3y = -1

Step-by-step explanation:

Standard form: Ax + By = C

Given: slope = 2/3 and  passes through the point (1,1)

Point slope form: y - y1 = m(x - x1)

Plug in

y - 1 = 2/3(x - 1)

Multiply both sides by 3

3(y - 1) = 2(x -1)

Distributive property

3y - 3 = 2x - 2

Since standard form: Ax + By = C so you can re-write the equation:

2x - 2 = 3y - 3

Subtract 3y from both sides

2x - 3y = -3

Add 2 to both sides

2x - 3y = -1

Answer in standard form: 2x - 3y = -1

You might be interested in
Find the distance d between 21 = (-7 - 6i) and Z2 = (-15 – 12i). Express your answer in exact terms and simplify, if needed.​
dlinn [17]

Answer:

10

Step-by-step explanation:

The distance is equal to the modulus of Z1-Z2.

Z_1 - Z_2 = -7 - 6i - (-15 - 12i) = 8 + 6i\\|8 + 6i| = \sqrt{8^2 + 6^2} = \sqrt{64 + 36} = \sqrt{100} = 10

8 0
3 years ago
6th Grade Math - Foster
amm1812

Answer:

4 weeks

38 hours

Step-by-step explanation:

First determine how much he makes each week

8.10 * 9.5 =76.95 per week

Multiply this by w  to determine the amount he will make in w weeks

76.95w

This must be greater than or equal to the amount he needs

76.95w ≥299.99

Divide each side by 76.95

76.95w/76.95  ≥299.99/76.95

w≥3.89851

Rounding to a whole number of weeks

4 weeks

4 weeks at 9.5 hours =

4* 9.5 =38 hours

6 0
4 years ago
Find the value for the side marked below.
Triss [41]

Answer:

y = 30.96

Step-by-step explanation:

take 23 degree as reference angle

using tan rule

tan 23 = opposite / adjacent

0.42 = 13/y

y = 13/0.42

y = 30.96

4 0
3 years ago
The function g has an inverse. The function g − 1 determines the number of folds needed to give the folded paper a thickness of
Amanda [17]

Answer:

\mathbf{g^{-1} (t) = log _2  \ 20 \ t}

Step-by-step explanation:

Here is the full question

A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times. We'll assume we can make "perfect folds," where each fold makes the folded paper exactly twice as thick as before - and we can make as many folds as we want.

Write a function g that determines the thickness of the folded paper (in mm) in terms of the number folds made, n. (Notice that g(0) 0.05,)

g(n )= (05)2^n

The function g has an inverse. The function g⁻¹ determines the number of folds needed to give the folded paper a thickness of t mm. Write a function formula for g⁻¹).

<u>SOLUTION:</u>

If we represent g(n) with  t;

Then

\mathbf{t = (0.05)2^n} \\ \\ \mathbf{\dfrac{t}{0.05} = 2^n} \\ \\ \mathbf{\dfrac {100 \ t }{ 5} = 2^n} \\  \\ \mathbf{20 t = 2^n}

Taking logarithm of both sides; we have :

\mathbf{log (20 t) = n log 2}    \ \ \    \mathbf{(since  \ ,  log  \ a^b = b \ log \ a) }  \\ \\ \mathbf{n =  \dfrac{log \ 20 t }{log \ 2 }} \\ \\ \mathbf{g^{-1} (t) =  \dfrac{log \ 20 t }{log \ 2 }} \\ \\ \mathbf{g^{-1} (t) = log _2  \ 20 \ t}

4 0
4 years ago
Help with both plz I’ll mark brainliest
LekaFEV [45]

Answer:

(1,6) is not a solution and I think the second one is: c I think

Step-by-step explanation:

5 0
3 years ago
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