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3 years ago

8 3/8 = r- 2 1/3 how do i solve this equation by finding out what r is.

1 answer:

7 0

First, convert your mixed numbers into improper fractions, so 8+3/8=69/8 and 2+1/3=7/3. Now you have 69/8=r-(7/3). Now, add 7/3 to both sides, so (69/8)+(7/3)=r. Now, just add your fractions, so (69/8)+(7/3)=207/24+56/24=(207+56)/24=263/24. If you need to, this can be converted back into the mixed number 10+23/24.

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3 years ago

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Answer:

$\cos\theta=\pm0.5$

Step-by-step explanation:

Given:

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To find $\cos\theta$

Using trigonometric relations for sums and differences of squares of the ratios.

We know:

$\sin^2\theta+\cos^2\theta =1$

Plugging in $\sin^2\theta=0.75$ in the above relation.

$0.75+\cos^2\theta =1$

Subtracting both sides by 0.75.

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Taking square root both sides.

$\sqrt{\cos^2\theta} =\sqrt{0.25}$

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3 years ago

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$x;\ y-the\ numbers\\\\ \left\{\begin{array}{ccc}xy=25\\x+y=-10&\to x=-10-y\end{array}\right\\\\subtitute:\\(-10-y)y=25\\(-10)(y)-y(y)=25\\-10y-y^2=25\\-y^2-10y-25=0\ \ \ \ |change\ the\ signs\\y^2+10y+25=0\\y^2+5y+5y+25=0\\y(y+5)+5(y+5)=0\\(y+5)(y+5)=0\\(y+5)^2=0\iff y+5=0\to \boxed{y=-5}\\\\subtitute\ the\ value\ of\ y\ to\ the\ equation\ x=-10-y\\x=-10-(-5)\\x=-10+5\\\boxed{x=-5}\\\\Answer:\boxed{-5\ and\ -5}$

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