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3 years ago

9

8 3/8 = r- 2 1/3 how do i solve this equation by finding out what r is.

1 answer:

BaLLatris [955]3 years ago

7 0

First, convert your mixed numbers into improper fractions, so 8+3/8=69/8 and 2+1/3=7/3. Now you have 69/8=r-(7/3). Now, add 7/3 to both sides, so (69/8)+(7/3)=r. Now, just add your fractions, so (69/8)+(7/3)=207/24+56/24=(207+56)/24=263/24. If you need to, this can be converted back into the mixed number 10+23/24.

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Bridget reads 5 pages of her book per day 4 days per week for several weeks.

Semenov [28]

It would be w(5•4) because she reads 20 pages in one week. then you can multiply 20 by any number of weeks to get that number of pages in total.

8 0

3 years ago

Below are the data collected from two random samples of 500 American adults on the number of hours they spend doing leisure and

ElenaW [278]

From the question we are told that:

Total Sample size n=500

Dan's mean \=x_D= 3hr

Bret's mean \=x_D= 4hr

Generally, the Total hours spent doing leisure and sports activities is mathematically given by

For Sample A

$T_a=(1*70)+(2*90)+(3*135)+(4*140)+(5*65)\\\\$

$T_a=1540 hours$

For Sample B

$T_b=(1*80)+(2*80)+(3*130)+(4*135)+(5*75)$

$T_b=1545$

Therefore

Average Time spent doing leisure and sports activities by an American Adult

For Sample A

$T_A=\frac{T_a}{n}$

$T_A=\frac{1540}{500}$

$T_A=3.08$

$T_A \approx 3$

For Sample B

$T_A'=\frac{T_b}{n}$

$T_A'=\frac{1545}{500}$

$T_A'=3.09$

$T_A' \approx 3$

Therefore

Dan is Correct because 3.08 or 3.09 is approximately equal to 3

7 0

3 years ago

A cable weighing 0.6 pounds per foot is attached to a small 80-pound robot, and then the robot is lowered into a 60-foot deep we

ollegr [7]

Answer:6060 foot-pounds

Step-by-step explanation:

Given

Weight of cable(w')=0.6 pound per foot

depth of well=60 foot

weight of wrench=7 Pound

Now work done in raising monkey with wrench $=w\cdot h$

$W_1=(80+7)\cdot 60=5220$ foot-pounds

Now work done in raising rope

robot rises by climbing up the cable with one end of the cable still attached thus robot support half the weight of cable so work done

$W_2==\int_{0}^{60}\frac{w'}{2}xdx$

$W_2=0.3\times 0.5\times (x^2)_0^{60}$

$W_2=540$ foot-pounds

$W_{net}=5220+540=6060$ foot-pounds

5 0

2 years ago

17.3152 to the nearest hundredth=

mamaluj [8]

Answer:

17.32

Step-by-step explanation:

since there is a 5 in the thousandths, we round the 1 in the hundredths up and get 17.32

3 0

2 years ago

How do you solve this problem?

umka21 [38]

The answer to your math question is x=5

7 0

2 years ago