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Yuri [45]
3 years ago
14

Solve 12−5x−4kx=y for x.

Mathematics
1 answer:
IgorC [24]3 years ago
5 0

Answer:

x = \frac{12-y}{4k+5}

Step-by-step explanation:

12-5x-4kx=y

1. Subtract 12 from both sides.

2.Distrubutive property (factor) a(b+c)=ab+ac

x(-5-4k)=y-12

  • Divide by -5-4k

x = \frac{y-12}{-5-4k}

= \frac{12-y}{4k+5}

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Solve for n: c= 6n−5g /11t
qwelly [4]

Answer: \frac{11tc+5g}{66t}=n

Step-by-step explanation:

You have the equation c=6n-\frac{5g}{11t}.

Then, to solve for the variable n from the equation you need:

Make the subtraction of the right side of the equation:

(As the denominators are 1 and 11t, the least common denominator is 11t)

c=\frac{(6n)(11t)-5g}{11t}\\\\c=\frac{66nt-5g}{11t}

Multiply  11t to both sides:

(11t)c=(\frac{66nt-5g}{11t})(11t)\\\\11tc=66nt-5g

Add 5g to both sides:

11tc+5g=66nt-5g+5g\\\\11tc+5g=66nt

And finally divide both sides by 66t:

\frac{11tc+5g}{66t}=\frac{66nt}{66t}\\\\\frac{11tc+5g}{66t}=n

3 0
3 years ago
Find all numbers whose absolute value is 3 . If there is more than one, separate them with commas. If there are no such numbers,
adelina 88 [10]

Answer:

3, and -3

Step-by-step explanation:

Because absolute value is the distance away from zero, |3| and |-3| would both be 3 units away from 0. Be sure to have the negative on the inside if you're trying to make something positive, otherwise -|3| means that the absolute value of 3 would then become negative since the negative sign isn't a part of the absolute. hope this helps!

3 0
3 years ago
Whats the average between these numbers:7.75,7.25,7.33,7.6?
satela [25.4K]

Step-by-step explanation:

Average between these no.s =

\frac{7.75 + 7.25 + 7.33 + 7.6}{4}

= 7.4825

= 7.5 approx

3 0
3 years ago
Which expression is 5 times as large as the expression 345+23
natima [27]

Answer:

1840

Step-by-step explanation:

345+23=368*5

3 0
2 years ago
Read 2 more answers
Evaluate the following double integral: xy dA D where the region D is the triangular region whose vertices are (0, 0), (0, 3), (
natulia [17]

Answer:

I= 84

Step-by-step explanation:

for

I=\int\limits^{}_{} \int\limits^{}_D {x*y}  \, dA =  \int\limits^{}_{} \int\limits^{}_D {x*y}  \, dx*dy

since D is the rectangle such that 0<x<3 , 0<y<3

I=\int\limits^{}_{} \int\limits^{}_D {x*y}  \, dA =  \int\limits^{3}_{0} \int\limits^{3}_{0} {x*y}  \, dx*dy =  \int\limits^{3}_{0} {x}  \, dx\int\limits^{3}_{0} {y}  \, dy  = x^{2} /2*y^{2} /2 =  (3^{2} /2 - 0^{2} /2)* (3^{2} /2 - 0^{2} /2) = 3^{4} /4 = 81/4

4 0
3 years ago
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