What is the value of a, if a^2 – 64 = 0 and a > 0?
A) 0
B) 4
C) 8
D) 16
1 answer:
A^2-64=0 you can factor like this:
(a+8)(a-8)=0 and since a>0, a must be 8
or you can do this:
add 64 to both sides of the equation leaving you with:
a^2=64 taking the square root of both sides
a=(-8,+8) and since a>0, a=8
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