What is the value of a, if a^2 – 64 = 0 and a > 0? A) 0 B) 4 C) 8 D) 16

1 answer:

5 0

A^2-64=0 you can factor like this:

(a+8)(a-8)=0 and since a>0, a must be 8

or you can do this:

add 64 to both sides of the equation leaving you with:

a^2=64 taking the square root of both sides

a=(-8,+8) and since a>0, a=8

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