(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
Answer:
anything x 0 is 0
Step-by-step explanation:
Answer:
2x =3
The hanger image given in the figure represents balanced equation.
Then we have to write an equation to represent the image.
In balanced form left side = right side
x + x = 1 + 1 + 1
2x = 3
Answer:
H (x= -3 , y=5)
I (x=8 , y=2)
J (x= -3 , y= -5)
D is the distance between the 2 points so just plug in the x and y cords of each of the corresponding points
so for (HI)
you plug in 2 on the red x
and 8 on the red y
then -3 in the blue x
and 5 in the blue y
Answer:
1 : 3
Step-by-step explanation:
1st Half: 9
2nd Half: 2(9)
Ratio = 2nd : 1st+2nd
9 : 9+2(9)
9 : 9 + 18
9 : 27
1 : 3
