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wel
4 years ago
11

Find the area. The figure is not drawn to scale.

Mathematics
2 answers:
dem82 [27]4 years ago
8 0

Hello!

To find our area, we multiply the base by the height and divide by 2.

as you can see, our base is 3.4 and our height is 8. To make it so we do not have to divide, we can just multiply by 4.

3.4(4)=13.6

Therefore, our area is 13.6 cm.

I hope this helps!

Ahat [919]4 years ago
7 0

A = 1/2 b h where b = 3.4 cm and h = 8 cm

A = 1/2 (3.4)(8)

A = 13.6 cm^2

Answer: 13.6 cm^2

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Write the first trigonometric expression in terms of the second expression. Cot(x); sin(x)
Alina [70]

The first trigonometric expression cot x and sin x in terms of the second expression is one over tan x and one over cosec x.

<h3>What is trigonometry?</h3>

Trigonometry deals with the relationship between the sides and angles of a right-angle triangle.

Write the first trigonometric expression in terms of the second expression.

The cotangent can be written as

\cot x= \dfrac{1}{\tan x}

And the sine can be written as

\sin x = \dfrac{1}{\csc x}

More about the trigonometry link is given below.

brainly.com/question/22698523

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3 years ago
Jason is collecting data on the number of books students read each year. What type of data is this?
tankabanditka [31]

Answer:

b. Discrete quantitative

Step-by-step explanation:

Hope that helps

7 0
4 years ago
You are creating a model of a bookcase for a dollhouse.
Goshia [24]

Answer:

If the model is 3 inches tall, the model bookcase should be <em>2 inches</em> wide.

Step-by-step explanation:

When using similar figures, set up a proportion of the model measurements to the actual measurements:

\frac{3}{48}=\frac{x}{32}

Then cross multiply and solve for x:

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6 0
3 years ago
In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s
Oksi-84 [34.3K]

Answer:

a) \mu_{\bar x} =\mu = 276.1

\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3

b) From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)

c) P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)

P(Z\geq2.070)=1-P(Z

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

\mu_{\bar x} =\mu = 276.1

\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3

Part b

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)

Part c

For this case we want this probability:

P(\bar X \geq 285)

And we can use the z score defined as:

z=\frac{\bar x -\mu}{\sigma_{\bar x}}

And using this we got:

P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)

And using a calculator, excel or the normal standard table we have that:

P(Z\geq2.070)=1-P(Z

8 0
3 years ago
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