In circle O, if LP congruent LK, find the measurement of the major arc PNK. A. 112 B.156 C.224 D.248

Michael earns $8 an hour to baby sit the Jackson family. How many hours does he have to 1 point

notsponge [240]

Answer:

7 hours

Step-by-step explanation:

56/8=7

7 0

3 years ago

Julia has 2 identical rooms in her house. If each room measures 8 fee on one side and 12 feet on another, what is the total area

Ksenya-84 [330]

Answer:

Step-by-step explanation:

all you have to is 8x12 multiplied by 2 since there is 2 rooms which is 192

5 0

3 years ago

Two tailors, Valentina and Laura, sit down to do some embroidery. Valentina can embroider 2 shirts per hour, and Laura can get t

mina [271]

Answer:

Valentina and Laura finished the same total number of shirts in $4$ hours.

Total number of shirts finished by Valentina $=23$

Total number of shirts finished by Laura $=23$

Step-by-step explanation:

Suppose that Valentina and Laura finished the same total number of shirts in $t$ hours.

Valentina can embroider 2 shirts per hour and Valentina has already completed 15 shirts.

Total number of shirts finished by Valentina $=2t+15$

Laura can get through 3 shirts per hour and Laura has completed 11 shirts.

Total number of shirts finished by Laura $=3t+11$

Therefore,

$2t+15=3t+11\\3t-2t=15-11\\t=4$

So,

Valentina and Laura finished the same total number of shirts in $4$ hours.

Total number of shirts finished by Valentina $=2(4)+15=8+15=23$

Total number of shirts finished by Laura $=3(4)+11=12+11=23$

6 0

2 years ago

Find the area of the regular polygon

Y_Kistochka [10]

Answer:

A = 374.123 ft^2

Step-by-step explanation:

First, lets calculate the perimeter:

Perimeter (p) = side length (s) * number of sides (n)

$p = s * n$

$p = 12 * 6$

$p = 72$

Next, lets find the apothem, which is the shortest length from any side to the middle. It's like the radius in a circle, but more complicated.

Apothem (a) = side length (s) / ( 2 * tan(180/number of sides (n)) )

$a = \frac{s}{2 * tan (\frac{180}{n} )}$

$a = \frac{12}{2 * tan (\frac{180}{6} )}$

$a = \frac{12}{2 * \frac{\sqrt{3} }{3}}$

$a = \frac{12}{\frac{2\sqrt{3} }{3}}$

$a = \frac{12*3}{2\sqrt{3}}$

$a = \frac{6*3}{\sqrt{3}}$

$a = \frac{18}{\sqrt{3}}$

Now, finally, to find the area of a regular polygon, we use the following equation:

Area (A) = ( apothem (a) * perimeter (p) ) / 2

$A = \frac{a * p}{2}$

$A = \frac{\frac{18}{\sqrt{3} } * 72}{2}$

$A = \frac{18}{\sqrt{3}} * 36$

$A = \frac{640}{\sqrt{3}}$

Turning into a decimal:

$A = 374.123 ft ^2$

8 0

2 years ago

Country Financial, a financial services company, uses surveys of adults age and older to determine if personal financial fitness

Yakvenalex [24]

Complete Question

Country financials, a financial services company, uses surveys of adults age 18 and older to determine if personal financial fitness is changing over time. In February 2012, a sample of 1000 adults showed 410 indicating that their financial security was more that fair. In Feb 2010, a sample of 900 adults showed 315 indicating that their financial security was more than fair.

a

State the hypotheses that can be used to test for a significant difference between the population proportions for the two years.

b

What is the sample proportion indicating that their financial security was more that fair in 2012?In 2010?

c

Conduct the hypothesis test and compute the p-value.At a .05 level of significance what is your conclusion?

Answer:

a

The null hypothesis is $H_o : p_1 = p_2$

The alternative hypothesis is $H_a : p_1 \ne p_2$

b

in 2012 $\r p_1 =0.41$

in 2010 $\r p_2 =0.35$

c

The p-value is $p-value = 0.0072$

The conclusion is

There is sufficient evidence to conclude that the proportion of those indicating that financial security is more fair in Feb 2010 is different from the proportion of those indicating that financial security is more fair in Feb 2012.

Step-by-step explanation:

From the question we are told that

The sample size in 2012 is $n_1 = 1000$

The number that indicated that their finance was more than fail is k = 410

The sample size in 2010 is $n_2 = 900$

The number that indicated that their finance was more than fail is u = 315

The level of significance is $\alpha = 0.05[/ex]The null hypothesis is [tex]H_o : p_1 = p_2$

The alternative hypothesis is $H_a : p_1 \ne p_2$

Generally the sample proportion for 2012 is mathematically represented as

$\r p_1 = \frac{k}{n_1}$

=> $\r p_1 = \frac{410}{1000}$

=> $\r p_1 =0.41$

Generally the sample proportion for 2010 is mathematically represented as

$\r p_2 = \frac{u}{n_2}$

=> $\r p_2 = \frac{315}{900}$

=> $\r p_2 =0.35$

Generally the pooled sample proportion is mathematically represented as

$\r p = \frac{k + u }{n_1 + n_2}$

=> $\r p = \frac{410 + 315 }{1000+ 900}$

=> $\r p = 0.3816$

Generally the test statistics is mathematically represented as

$z = \frac{( \r p_1 - \r p_2 ) - 0}{\sqrt{\r p (1 - \r p ) ( \frac{1}{n_1} +\frac{1}{n_2} )} }$

$z = \frac{( 0.41 -0.35 ) - 0}{\sqrt{0.3816 (1 - 0.3816 ) ( \frac{1}{1000} +\frac{1}{900} )} }$

$z = 2.688$

Generally the p- value is mathematically represented as

$p-value = 2 P(Z >2.688 )$

From the z -table

$P(Z > 2.688) = 0.0036$

So

$p-value = 2 *0.0036$

$p-value = 0.0072$

So from the p-value obtained we see that p-value < $\alpha$ so we reject the null hypothesis

Thus there is sufficient evidence to conclude that the proportion of financial security is more fair in Feb 2010 is different from the proportion of financial security is more fair in Feb 2012.

5 0

3 years ago