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3 years ago

Simplify (5x^7y^3z^-1)^2x(2xy^-5)^3x(2y^-3z^2)^3

1 answer:

8 0

Remember
$(abc)^x=(a^x)(b^x)(c^x)$
and
$(x^m)(x^n)=x^{m+n}$
and
$(x^m)^n=x^{mn}$
and
$x^{-m}= \frac{1}{x^m}$
so

$(5x^7y^3z^{-1})^2(2xy^{-5})^3(2y^{-3}z^2)^3$ =
$(5^2)((x^7)^2)((y^3)^2)((z^{-1})^2)(2^3)(x^3)((y^{-5})^3)(2^3)((y^{-3})^3)((z^2)^3)$ =
$(25)(x^{14})(y^6)(z^{-2})(8)(x^3)(y^{-15})(8)(y^{-9})(z^6)$ =
$1600x^{17}y^{-18}z^4$ =
$\frac{1600x^{17}z^4}{y^{18}}$

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Would anyone please be able to help me??

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Answer:

Area of first shape = 97cm^2

Area of second shape = 506cm^2

Area of third shape =143 cm^2

First shape :

i. Area if rectangle in the fig. = l*b

= 12*4

= 48 cm^2

Now, in the same fig. we construct a line and make it a square,

ii. Area of square = s*s

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Area of whole shape = 48cm^2 + 49cm^2

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Second Shape :

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ii. Area of the rectangle (stick like shape)

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Area of whole shape = (100 + 406) cm^2

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Third shape :

i. Area of the triangle = 1/2 *b* h

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ii. Area of the square = s*s

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